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jenyasd209 [6]
2 years ago
6

Find two numbers whose sum is 15 and whose product is as large as possible.

Mathematics
1 answer:
Zanzabum2 years ago
6 0
If one number is x the other is 15-x so their product is 15x-x².
This can be written -(x²-15x+225/4)+225/4=(15/2)²-(x-15/2)².
The largest value of this expression is when x=15/2=7.5 so the other number is also 7.5.
Let’s pick two other numbers and check their product: 7 and 8, product=56 but the product of 7.5 and 7.5=56.25 which is larger, therefore the two numbers are 7.5 and 7.5.
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Andru [333]

Answer:

y= -3x+4

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Step-by-step explanation:

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2 years ago
9.The perimeter of a rectangle whose length is 7.5cm and breadth 3.75cmRequired to answer. Single choice.​
BabaBlast [244]

Answer:

22.5 cm

Step-by-step explanation:

P = 2( L + W)

P = 2( 7.5 + 3.75)

P = 2( 11.25)

P = 22.5 cm

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In a poll, 6 out of 13 children said they read every night before bed, whereas 54% of the adults said they read every night befo
Tpy6a [65]
To answer this question you must find the percentage of the children that read before bed and compare it to the adults bag read before bed’s percentage.
To do this, start by dividing the number of children that read before bed by the total number of children surveyed.
This leaves you with:
6/13= 0.4615

To find the actual percentage, multiply this result by 100.
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This percentage rounded is 46%

So, now you can compare the percentages. The percentage of children that read before bed is 46% and the percentage of adults that read before bed is 54%. So, the group with the greatest percentage was the adults.

I hope this helps!
3 0
2 years ago
Which expression should you simplify to find the 90% confidence interval,
Alex787 [66]

Answer:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287

0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is \hat p=0.45

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value is:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the true population proportion is interest is given by this formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the values provided we got:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287

0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

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2 years ago
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