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jenyasd209 [6]
3 years ago
6

Find two numbers whose sum is 15 and whose product is as large as possible.

Mathematics
1 answer:
Zanzabum3 years ago
6 0
If one number is x the other is 15-x so their product is 15x-x².
This can be written -(x²-15x+225/4)+225/4=(15/2)²-(x-15/2)².
The largest value of this expression is when x=15/2=7.5 so the other number is also 7.5.
Let’s pick two other numbers and check their product: 7 and 8, product=56 but the product of 7.5 and 7.5=56.25 which is larger, therefore the two numbers are 7.5 and 7.5.
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Answer:

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Step-by-step explanation:

Given

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Required

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Open bracket

V = \frac{4}{3}\pi * \frac{3}{2}^3 * x^{3*3}y^{-2*3}

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Simplify the fractions

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Let

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So:

V = \frac{22}{7}  * \frac{9}{2} * x^{9}y^{-6}

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V = \frac{99}{7}   * x^{9}y^{-6}

V = \frac{99}{7} x^{9}y^{-6}

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Answer:

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Step-by-step explanation:

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I hope this helps...

:)

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