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3 years ago

What is the equation for the line?

Mathematics

1 answer:

svetlana [45]3 years ago

4 0

Y=ax+b
when x=2, y=16
x= -2, y= -16

2a +b= 16
-2a+b = -16
----------------
/ 2b=0

2b=0, b=0
2a=16, a=16:2, a=8
the equation is y= 8x

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2. Multiply and simplify: (x - 2)(2x + 3) Answer

inysia [295]

Step-by-step explanation:

(x - 2)(2x + 3)

=2x²+3x-4x-6

=2x²-x-6

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3 years ago

Read 2 more answers

-6x - y = 27 3x + 8y = 9

attashe74 [19]

Answer:

-6x - y = 27 = x= −1 /6 y+ −9 /2

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Step-by-step explanation:

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3 years ago

How do you find the value of c that satisfy the equation:

victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

Step(i):-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

Mean Value theorem

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

$f^{l} (c) = \frac{f(b) -f(a)}{b-a}$

Step(ii):-

Given f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

f¹(x) = 4(2x) +4(1) = 8x+4

Step(iii):-

By using mean value theorem

$f^{l} (c) = \frac{f(0) -f(-1)}{0-(-1)}$

$8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}$

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

$c = \frac{-4}{8} = \frac{-1}{2} = -0.5$

c ∈ (-1,0)

Conclusion:-

The value of c = -0.5∈ (-1,0)

8 0

3 years ago

The price of a stock rose from a yearly low of $9.68 to $18.61. what was the stock percent increase from its low price that year

Helga [31]

Answer: i think it is 8.93

Step-by-step explanation:

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3 years ago

use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 ), (15 comma

lyudmila [28]

Answer:

volume V of the solid

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.

Each slice is a quarter of cylinder 5/n thick and has a radius of

-k(5/n) + 5 for each k = 1,2,..., n (see picture)

So the volume of each slice is

$\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}$

for k=1,2,..., n

We then add up the volumes of all these slices

$\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}$

Notice that the last term of the sum vanishes. After making up the expression a little, we get

$\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2$

But

$\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)$

we also know that

$\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}$

and

$\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}$

so we have, after replacing and simplifying, the sum of the slices equals

$\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}$

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

$\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}$

and the volume V of our solid is

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

3 0

3 years ago