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alexandr402 [8]

4 years ago

10

I WILL MARK BRAINLIEST ON ALL PLEASE HELP

1 answer:

gladu [14]4 years ago

7 0

5 the answer is B 6 the answer is D

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How are intermolecular forces of attraction, vapor pressure, and boiling point related?

monitta

Answer:

Intermolecular forces (IMFs) can be used to predict relative boiling points. The stronger the IMFs, the lower the vapor pressure of the substance and the higher the boiling point. Therefore, we can compare the relative strengths of the IMFs of the compounds to predict their relative boiling points.

Explanation:

7 0

3 years ago

What type of bonding occurs in potassium oxide, k2o?

Naya [18.7K]

Would be considered as an iconic bond.

6 0

3 years ago

Which answer below is not an indication that a chemical reaction has occurred?

ankoles [38]

Only when there is no product that is when a chemical reaction has not occured

4 0

4 years ago

Which of the following is not an example of a molecule?

9966 [12]

D. F

Molecules are a group of bonded atoms but Fluorine stands on its own

4 0

4 years ago

Read 2 more answers

When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot

viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the $'n^{th}'$ orbit of hydrogen atom.

Formula used :

$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

$E_n$ = energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

$E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV$

Energy of n = 2 in an hydrogen atom:

$E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV$

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

$E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV$

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0

3 years ago