Answer:
Specific Rotation = 105º
S% in mixture = 92%
Explanation:
Specific rotation in organic compounds varies linearly, then the enantiomeric excess can be express as:
Where alpha is the specific rotation of the mixture and alpha pure is the specific rotation of the excess enantiomer.
Then, knowing that the S enantiomer is in excess you can calculate the specific rotation of that mixture:
For calculating the percentage of S you should remember that the enantiometric excess is the percentage of excess of a certain enantiomer, for example in this case:
Since S is in Excess
Also, it is true:
Then you can solve the system of linear equations, finding:
Hope it helps!
Radiation is the only way heat is transferred that can move through the relative emptiness of space. All other forms of heat transfer require motion of molecules like air or water to move heat.
The first step is to establish a goal and write it down. This adds commitment and you are declaring your intentions.
The second step is write down your daily plan of action. A plan without action is as useless if you had never written the goal at all.
The third step is to share your goal with someone who will hold you accountable. They can share your victories , failures, and provide encouragement.
The final step is to act on that plan. You must take action now that you have all the tools.
While metallic bonds have the strong electrostatic force of attractions between the cation or atoms and the delocalized electrons in the geometrical arrangement of the two metals. ... Metallic bonds are malleable and ductile, while covalent bonds and ionic bonds non-malleable and non-ductile.
According to Arrhenius theory of acid and bases, an acid is a proton donor, while base donates hydroxyl ions. Further, acid and base reacts to form salt and water.
Consider following example.
HCl + H2O → Cl- + H3O+
here, HCl has donated a proton, hence it is an acid.
Now consider following reactionHCl + NaOH ↔ NaCl + H2O
in this reaction, HCl donates proton, hence it is acid. On other hand, NaOH donates hydroxyl ion (i.e. OH-), hence it is a base.
