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3 years ago

Is this the right answer? Help.

Chemistry

1 answer:

Rus_ich [418]3 years ago

7 0

I accidentally clicked on this, I know nothing about chemistry, but you have pretty handwriting.

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If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?

vovikov84 [41]

The reaction between hydrogen and oxygen to form water is given as:

$H_2 + O_2 \rightarrow H_2O$

The balanced reaction is:

$2H_2 + O_2 \rightarrow 2H_2O$

According to the balanced reaction,

4 g of hydrogen ( $4\times 1$ ) reacts with 32 g of oxygen ( $2\times 16$ ).

So, oxygen reacted with 29.4 g of hydrogen is:

$\frac{29.4\times 32}{4} = 235.2 g$

Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

7 0

3 years ago

Please help I will give brainliest.

iris [78.8K]

Answer:

the second one looks like it so I picked the second one

8 0

2 years ago

Write an equation and solve the problem.

VMariaS [17]

Dexter already has 4 and he gets 38 so 4+38=42. Than 42/6=7. 7 plates on each table.

4 0

2 years ago

Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2

Flauer [41]

Answer:

$\boxed{28.81}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 58.12 44.01

2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g: 9.511

1. Moles of C₄H₁₀

$\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}$

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

$\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}$

3. Mass of CO₂

$\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}$

8 0

2 years ago

Calculate the cell potential, Ecell, of a concentration cell containing a 0.1 M solution of Zn2 and a 1.0 M solution of Zn2

Agata [3.3K]

Answer:

The cell potential is 0.0296V

Explanation:

Please see the attachment below

3 0

3 years ago