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Kipish [7]
3 years ago
5

If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?

Chemistry
1 answer:
padilas [110]3 years ago
4 0

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

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Answer:

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Explanation:

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We want to calculate the number of silver nitrate (AgNO3) moles that would be produced from 52 moles of nitric acid ( HNO3 )

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The mole ratio of Silver nitrate to nitric acid based on the balanced equation is 3AgNO3:4HNO3.

Using this we can create a table: The table is attached.

Breakdown of the table.

The moles of nitric acid cancel out and we multiply 52 by 3/4 to get 39 moles of Silver nitrate.

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