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2 years ago

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A gas effuses 4.0 times faster than oxygen (o2). what is the molecular mass of the gas? 1.0 g/mol 1.0 g/mol 2.0 g/mol 2.0 g/mol

4.0 g/mol 4.0 g/mol 7.67 g/mol

1 answer:

Anastaziya [24]2 years ago

5 0

Answer:

32(molecular mass has no unit )

Explanation:

(16)(o2)

16×2

=32

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A cube of steel with a mass of 150 grams is heated from 60°C to 150°C.

yan [13]

Answer:

1.

The energy lost by the water is given by:

where

m = 3.0 kg = 3000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

is the change in temperature

Substituting,

2.

The energy added to the aluminium is given by:

where

m = 0.30 kg = 300 g is the mass of aluminium

Cs = 0.900 J/g•°C is the specific heat

is the change in temperature

Substituting,

4. 42.9 g

The mass of the water sample is given by

where

is the heat added

is the temperature change

Cs = 4.179 J/g•°C is the specific heat

5. 115.5 J

The heat used to heat the copper is given by:

where

m = 5.0 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

is the change in temperature

6. 0.185 J/g•°C

The specific heat of iron is given by:

where

Q = -47 J is the heat released by the iron

m = 10.0 g is the mass of iron

is the change in temperature

Substituting,

Substituting,

Substituting,

Explanation:

8 0

3 years ago

How many moles of oxygen are needed to react with 87 grams of aluminum

labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s) + 3O₂(l) → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

Al : O₂

4 : 3

3.2 : 3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

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2 years ago

13.8g element consist 4.6 ×10^22 atoms what is atomic mass of element?

Keith_Richards [23]

<h2>~<u>Solution</u> :-</h2>

Here, to find the atomic mass of element, we must;

We know that,

4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.

Thus,

The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;

$= \sf{\frac{13.8 \times 6.02 \times {10}^{23} }{4.6 \times {10}^{22} } } \\$

$= \sf{180.6 \: g \: \: (molar \: mass)}$

Hence, the molar mass (atomic mass) will be <u>180.6 g.</u>

8 0

2 years ago

Read 2 more answers

Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.

mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

7 0

2 years ago

I need chemistry help text me at (951) 897-8325 PLEASE

user100 [1]

Just post the question on here

7 0

2 years ago