Question

In a reaction, a + b + c→ d, it is found that the reaction is first order in terms of a and second order in terms of b and half order in terms of
c. what happens to the rate if the concentrations of a and c are doubled and b remains the same?

Answer 1

Rate=[a]*([b]^2)*([c]^(1/2)]
rate=[2a]*([b]^2)*([2c]^(1/2)]= 2*(2^(1/2)[a]*([b]^2)*([c]
it increases  times 2*(2^(1/2)=2√2