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Annette [7]
3 years ago
11

Which of these is a benefit of fuel cell cars?

Chemistry
2 answers:
Vesnalui [34]3 years ago
7 0

Answer:

a

Explanation:

Otrada [13]3 years ago
5 0

Answer:

A.

Explanation:

There are no vehicle emissions other than water vapor. This means no pertroleum products and no fossil fuels. :)

-Sienna Sushi

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Which of the following is a benefit of having a standard measurement system that can be used by scientists worldwide?
bonufazy [111]
2. Scientists can compare and share data with each other. 

By making use a standard measurement system scientists can accurately share data with one another and use this as the basis for further scientific research .

For example a scientist can further research an experiment by simply using a standard measurement or conversion to better or even perfect an experiment .
6 0
3 years ago
Which objects will most likely float
storchak [24]
Sponges, apples, light weight balls, etc.
they’re less dense than water
6 0
4 years ago
Consider the reaction data.
Snowcat [4.5K]

Answer:

(a) x₁= 0.004 444; (b) y₁ = -0.9545; (c) x₂ = 0.001 905; (d) y₂ = -0.4541;

(e) rise = 0.5004; (f) run = -0.002 539; (g) slope = -197.1; (h) Eₐ = -1.64 kJ·mol⁻¹

Explanation:

This is an example of the Arrhenius equation:

k = Ae^{-E_{a}/RT}\\\text{Take the ln of each side}\\\ln k = \ln A - \dfrac{E_{a}}{RT}\\\\\text{We can rearrange this to give}\\\ln k = -\left ( \dfrac{E_{a}}{R} \right )\dfrac{1}{T} + \ln A

Thus, if you plot ln k vs 1/T, you should get a straight line with slope = -Eₐ/R and a y-intercept = lnA

(a) x₁

x₁= 1/T₁ = 1/225 = 0.004 444

(b) y₁

y₁ = ln(k₁) = ln0.385 = -0.9545

(c) x₂

x₂= 1/T₂ = 1/525 = 0.001 905

(d) y₂

y₂ = ln(k₂) = ln0.635 = -0.4541

(e) Rise

Δy = y₂ - y₁ = -0.4541 - (-0.9545) = -0.4541 + 0.9545 = 0.5004

(f) Run

Δx = x₂ - x₁ = 0.001 905 - 0.004 444  = -0.002 539

(g) Slope

Δy/Δx = 0.5004/(-0.002 539) K⁻¹ = -197.1

(h) Activation energy

Slope = -Eₐ/R

Eₐ = -R × slope = -8.314 J·K⁻¹mol⁻¹ × (-197.1 K⁻¹) = 1638 J/mol = 1.64 kJ/mol

3 0
3 years ago
What is the total mass of NaNO3 that must be added to 70g in 100 grams of H2O to make a saturated solution at 30°C ?
dimulka [17.4K]

Answer:

58g

Explanation:

In order to solve this problem, you must take a look at the solubility graph for potassium nitrate.

Now, the solubility graph shows you how much solute can be dissolved per 100g of water in order to make an unsaturated, a saturated, or a supersaturated solution.

You're looking to make a saturated potassium nitrate solution using

50g of water at 60∘C. Your starting point will be to determine how much potassium nitrate can be dissolved in 100g of water at that temperature in order to have a saturated solution.

As you can see, the curve itself represents saturation.

If you draw a vertical line that corresponds to 60∘C and extend it until it intersects the curve, then draw a horizontal line that connects to the vertical axis, you will find that potassium has a solubility of about

115g per 100g of water. Your answer is 58g of potassium nitrate

7 0
4 years ago
Under what conditions will deviations from the "ideal" gas be expected?
mixas84 [53]

Answer:

Conditions which results in deviating a gas from "ideal" behavior are

1. Low Temperature

2. High Temperature

Explanation:

Ideal gas according to the kinetic model theory states that the conditions that apply are high temperatures where kinetic energy and low pressure is too high and the interactions in between and the container are negligible. Hence, the deviations of ideal gas falls when there is low temperature and high pressure.

3 0
3 years ago
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