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3 years ago

Uranium-236 is ____.

Chemistry

2 answers:

Scrat [10]3 years ago

4 0

Answer:

A. Created by fusion reactions

Explanation:

happy to help :)

wolverine [178]3 years ago

3 0

Answer: The correct answer is a.

Uranium-236 is intermediate nuclei created by fusion reactions an unstable isotopes of uranium created from four hydrogen atoms used in the H - bomb .

Following is the reaction involved in above process :

²³⁵U + ¹n = ²³⁶U = ¹⁴⁴Ba + ⁸⁹ Kr + 3¹n + 177 MeV

Here ,

²³⁵U = Fision Material ,

¹n = projectile ,

²³⁶U = Intermediate Nuclei

¹⁴⁴Ba and ⁸⁹ Kr = Fission product

Explanation:

hope it helps !

brainliest plzz :)))

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What qualifies someone to be one is someone who systematically gathers and uses research and evidence making a hypothesis and testing it to gain and share understanding and knowledge.

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3 years ago

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Answer:

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2 years ago

Explain what will happen to the organisms that is affected by human activities.

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Answer:

Human activity is by far the biggest cause of habitat loss.

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Explanation:

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One of the most significant ways in which humans have impacted on the lives of other species is by causing climate change. Many animals, including birds and frogs, now breed much earlier in spring in Britain than they did 20 years ago. Whether or not this is having a harmful effect on them has yet to be determined.

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3 years ago

How does a buffer resist change in ph upon addition of a strong acid?

lora16 [44]

Any buffer exists in this equilibrium

HA <=> $H^+ + A^-$
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base ( $A^-$ )

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3 years ago

An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of

RSB [31]

Answer:

$V=0.0310L=3.10mL$

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

$n_{acid}=n_{KOH}$

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

$n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol$

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

$V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL$

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2 years ago