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3 years ago

Uranium-236 is ____.

Chemistry

2 answers:

Scrat [10]3 years ago

4 0

Answer:

A. Created by fusion reactions

Explanation:

happy to help :)

wolverine [178]3 years ago

3 0

Answer: The correct answer is a.

Uranium-236 is intermediate nuclei created by fusion reactions an unstable isotopes of uranium created from four hydrogen atoms used in the H - bomb .

Following is the reaction involved in above process :

²³⁵U + ¹n = ²³⁶U = ¹⁴⁴Ba + ⁸⁹ Kr + 3¹n + 177 MeV

Here ,

²³⁵U = Fision Material ,

¹n = projectile ,

²³⁶U = Intermediate Nuclei

¹⁴⁴Ba and ⁸⁹ Kr = Fission product

Explanation:

hope it helps !

brainliest plzz :)))

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3Co2 (aq) 6NO3(aq) 6Na (aq) 2PO43–(aq) → Co3(PO4)2(s) 6Na (aq) 6NO3(aq) Identify the net ionic equation for this reaction.

Burka [1]

Answer : The net ionic equation will be,

$3Co^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Co_3(PO_4)_2(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$3Co^{2+}(aq)+6NO_3^-(aq)+6Na^+(aq)+2PO_4^{3-}(aq)\rightarrow Co_3(PO_4)_2(s)+6Na^+(aq)+6NO_3^-(aq)$

In this equation, $NO_3^-(aq)\text{ and }Na^+(aq)$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

Thus, the net ionic equation will be,

$3Co^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Co_3(PO_4)_2(s)$

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