Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
In this case, the percent composition of fluorine is:
percent composition of fluorine= 65.67%
<u><em>The percent composition of fluorine is 65.67%</em></u>
Answer:
A: Antibonding molecular orbitals are higher in energy than all of the bonding molecular orbitals.
Explanation:
Molecular orbital theory describes <u>covalent bonds in terms of molecular orbitals</u>, which result from interaction of the atomic orbitals of the bonding atoms and are associated with the entire molecule.
A bonding molecular orbital has lower energy and greater stability than the atomic orbitals from which it was formed. An antibonding molecular orbital has higher energy and lower stability than the atomic orbitals from which it was formed.
Electrons in the antibonding molecular orbital have higher energy (and less stability) than they would have in the isolated atoms. On the other hand, electrons in the bonding molecular orbital have less energy (and hence greater stability) than they would have in the isolated atoms.
True, because diatomic elements (H2, O2, F2, Br2, I2, N2, Cl2) consist of only one element but are molecules with covalent bonds.
Answer:
4.09ₓ10²³ atoms are contained in 10g of C₃H₈
Explanation:
1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.
1 mol of C₃H₈ weighs 44 g
In 44 g of C₃H₈ we have 3 mol of C
In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol
1 mol of C has NA (6.02x10²³) particles
0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms
"It reacts with water" is incorrect I took the test and got it wrong. I believe it is B, because oxygen combines with glucose and makes carbon dioxide.
