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vlabodo [156]
3 years ago
5

Is slime a liquid or solid?

Chemistry
2 answers:
9966 [12]3 years ago
8 0

Answer:

a <u>non-</u><u> </u>NEWTONIAN liquid, which means viscosity, and or resistance, of the liquid changes as you apply stronger force

guajiro [1.7K]3 years ago
4 0

its kinda hard to tell? What type of slime? I mean does it take up the shape of a container or does it just stay how you make it?

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Two moles of neon gas enclosed in a constant volume system receive 4250 J of heat. If the gas was initially at 293 K, what is th
Veseljchak [2.6K]

Answer:

<u><em>=355.5K</em></u>

Explanation:

Specific heat, Q = mcΔT

where

  • Q= 4250J
  • ΔT= change in temp = final temp - initial temp
  • c = specific heat capacity = 1.7
  • m = mass of substance in grams

[1 mole of Ne = 20g; 2 moles of Ne = 2 × 20 = 40g]

4250 = 40 × 1.7 × (final - 293K)

final - 293k = 4250 / ( 40 × 1.7)

Final temp = 62.5 + 293

<em>=355.5K</em>

I hope this steps are simple to follow and understand.

3 0
3 years ago
When the temperature of a reacting mixture increases, the rate of reaction increases. Which statement explains why the rate of r
wlad13 [49]

Answer:

This is one of the factors that affects chemical reactions

Temperature:This is because when the temperature is raised energy in form of heat is supplied to the reacting particles and so the rate of reaction is increased.

3 0
4 years ago
Which is/are used in nuclear reactors to absorb neutrons?
daser333 [38]

Answer:

A. heavy nuclei

Explanation:

They absorb neuyrons in order to hain stability.

8 0
3 years ago
Read 2 more answers
Balance the equation of. _C + _O2 -- _CO
scoundrel [369]

Explanation:

2C +O2 = 2CO

this will be the answer

8 0
3 years ago
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr
jenyasd209 [6]

Answer : The final temperature of the water is, 22.5166^oC

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives \frac{6542 kJ}{2}\times 0.1103=360.7913kJ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})

where,

q_w = heat released = 360.7913 kJ = 36079.13 J

m_w = mass of water = 5691 g

c_w = specific heat of water= 4.18J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 21^oC

Now put all the given values in the above formula, we get:

36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)

T_{final}=22.5166^oC

Therefore, the final temperature of the water is, 22.5166^oC

8 0
4 years ago
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