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Virty [35]
1 year ago
10

A sample of gas has its number of molecules quadrupled, its Kelvin temperature doubled, and its volume tripled. By what factor h

as the new pressure changed relative to the original pressure
Chemistry
1 answer:
steposvetlana [31]1 year ago
4 0

The new pressure changed relative to the original by a factor of 8/3.

<h3>What is the change in the pressure?</h3>

Using the ideal gas equation;

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

P1 = nRT/V

P2 = 4n * R * 2T/3V

Hence;

P2/P1 = 4n * R * 2T/3V ÷  nRT/V

P2/P1 = 4n * R * 2T/3V * V/nRT

P2/P1 =4 * 2/3

= 8/3

Learn more about ideal gas law:brainly.com/question/13821925

#SPJ1

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Explanation:

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In order to be able to answer the question accurately you have to have the tables containing all the values for chemical shift. The Chemical shift is measured in ppm and it occur due to Resonance frequency variation.

From the table, a singlet at 1.15 ppm (9H) is - C(CH3)3.

A singlet at d 0.9 ppm (1H) shows the presence of a secondary amine group, that is -R2NH group.

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Kindly check attached file for the picture of the structure.

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