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Virty [35]
1 year ago
10

A sample of gas has its number of molecules quadrupled, its Kelvin temperature doubled, and its volume tripled. By what factor h

as the new pressure changed relative to the original pressure
Chemistry
1 answer:
steposvetlana [31]1 year ago
4 0

The new pressure changed relative to the original by a factor of 8/3.

<h3>What is the change in the pressure?</h3>

Using the ideal gas equation;

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

P1 = nRT/V

P2 = 4n * R * 2T/3V

Hence;

P2/P1 = 4n * R * 2T/3V ÷  nRT/V

P2/P1 = 4n * R * 2T/3V * V/nRT

P2/P1 =4 * 2/3

= 8/3

Learn more about ideal gas law:brainly.com/question/13821925

#SPJ1

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What is the molarity of a solution that contains 0.082 mol KI in a 2.03 L solution?
astraxan [27]

Answer:

molarity of the KI solution = 0.04 mol/L

Explanation:

Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution.  

The law that we can applied to calculate the M is:  

M = n / V

n - number of moles

V- volume of the solution (liters)

Then insert in the equation the values from the question;  

M = 0.082 mol  /  2.03 L = 0.04 mol/L

4 0
3 years ago
What element has 80 protons, 81 neutrons, 79 electrons?
Mariana [72]

Answer:

The element will be ^{161}_{80}X

Explanation:

Given that,

Number of proton = 80

Number of neutron = 81

Number of electron = 79

We know that,

The atomic number is equal to the number of proton.

So, the atomic number is 80.

According to atomic number,

The element will be mercury.

We need to calculate the atomic mass

Using formula of atomic mass

atomic\ mass=atomic\ number+number\ of\ neutron

Put the value into the formula

atomic\ mass=80+81

atomic\ mass=161

We need to find the element

Using atomic mass and atomic number

atomic\ mass\ number A=161

atomic\ number Z=80

So, the element will be

^{A}_{Z}X

Put the value of A and Z

Hence, The element will be ^{161}_{80}X

5 0
3 years ago
Compare the values of the spin quantum number for two electrons in the same orbital.
atroni [7]
Private school and the cashapp one of my favorite classes and I can get it
6 0
3 years ago
Calculate the EMF of the following cell at standard conditions (temperature = 25o C, pressure = 1 atmosphere): Ni | Ni2+ | | Cu2
kakasveta [241]

Answer:

a) +0.574 V

b) +0.573V

Explanation:

The EMF is the electromotive force, which is the property of a device that intends to generate electrical current. The EMF of a cell can be calculated by the Nernst equation:

Emf = E° - (0.0592/n)*logQ

Where E° is the standard reduction potential of the cell, n is the number of electrons involved in the reaction, and Q is the reaction quotient ([products]/[reactants]).

In the cell, a redox reaction happens. One substance oxides (lose electrons and become a cation), and the other one reduces (gains electrons and becomes an anion). Each reaction has a reduction potential (E), which indicates how easily is to the reduction happens (as higher E as easy).

For the overall reaction, E° = Ereduction - Eoxidation. To the cell given, Ni is oxidizing, and Cu⁺² is reducing, so, the half-reactions with its E (which can be found at tables), and the overall reaction are:

Ni(s) → Ni⁺² + 2e⁻ E = -0.24 V

Cu⁺² + 2e⁻ → Cu(s) E = +0.337 V

Ni(s) + Cu⁺² → Ni⁺² + Cu(s)

E° = +0.337 - (-0.24)

E° = +0.577 V

As we can see, there're 2 electrons involved in the reaction, so n =2.

The solids don't take place in the Q value, so:

Q = [Ni⁺²]/[Cu⁺²]

a) Q = 0.1/0.08 = 1.25

Emf = 0.577 - (0.0592/2)*log(1.25)

Emf = 0.577 - 0.003

Emf = +0.574 V

b) Q = 0.4/0.3 = 1.33

Emf = 0.577 - (0.0592/2)*log(1.33)

Emf = 0.577 - 0.004

Emf = +0.573 V

3 0
3 years ago
What is the freezing point of a solution containing 4.78 grams naphthalene (molar mass = 128.2 g/mol) dissolved in 32.0 grams pa
tester [92]
This is a freezing point depression problem, so it will use the equation:

ΔT = i Kf<span> m
</span>
i = 1 (naphthalene does not dissociate further when dissolved)
Kf = 7.10 C/m (a constant for paradichlorobenzene, which you'd be given)
m = moles of solute / kg of solvent; moles of solute = 4.78 / 128.2 = 0.0373; kg of solvent = 0.032; m = 0.0373 / 0.032 = <span>1.166m

</span>ΔT = 1 x 7.10 x 1.166 = 8.279 C

This means the normal freezing point of pure paradichlorobenzene is decreased by 8.279 C; the normal freezing point (again, something you'd be given) is 53.5 C, so the new freezing point would be 53.5 - 8.279 = 45.221 C.
4 0
3 years ago
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