A sample of gas has its number of molecules quadrupled, its Kelvin temperature doubled, and its volume tripled. By what factor h

Question

2 years ago

10

as the new pressure changed relative to the original pressure

1 answer:

steposvetlana [31] · Answer 1 · 2023-09-15T12:52:45+03:00

The new pressure changed relative to the original by a factor of 8/3.

<h3>What is the change in the pressure?</h3>

Using the ideal gas equation;

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

P1 = nRT/V

P2 = 4n * R * 2T/3V

Hence;

P2/P1 = 4n * R * 2T/3V ÷ nRT/V

P2/P1 = 4n * R * 2T/3V * V/nRT

P2/P1 =4 * 2/3

= 8/3

Learn more about ideal gas law:brainly.com/question/13821925

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