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Nuetrik [128]
3 years ago
9

A solution of acetic acid has an equilibrium pH of 2.54 (pKa = 4.75). What was the original concentration of acetic acid?

Chemistry
2 answers:
charle [14.2K]3 years ago
4 0

Answer:

A:0.469 molar

Explanation:

It is right

andrezito [222]3 years ago
3 0

Answer:

i cant under stand what you are trying to say

Explanation:

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Which is the smallest part of a compound called?
lidiya [134]
The answer is molecule

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4 years ago
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What is the main difference between extensive and intensive physical properties?
mr_godi [17]
Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present.
8 0
3 years ago
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What is the wavelength of a photon with an energy of 3.50 x 10^-19 J ?
Leokris [45]

Answer:

λ = 5.68×10⁻⁷ m

Explanation:

Given data:

Energy of photon = 3.50 ×10⁻¹⁹ J

Wavelength of photon = ?

Solution:

E = hc/λ

h = planck's constant = 6.63×10⁻³⁴ Js

c = 3×10⁸ m/s

Now we will put the values in formula.

3.50 ×10⁻¹⁹ J =  6.63×10⁻³⁴ Js × 3×10⁸ m/s/ λ

λ =  6.63×10⁻³⁴ Js × 3×10⁸ m/s / 3.50 ×10⁻¹⁹ J

λ =  19.89×10⁻²⁶ J.m / 3.50 ×10⁻¹⁹ J

λ = 5.68×10⁻⁷ m

8 0
3 years ago
What kinds of elements form an ionic bond?
Vanyuwa [196]
Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl. In a covalent bond, the atoms bond by sharing electrons. Covalent bonds usually occur between nonmetals.
5 0
3 years ago
19.3 g of cadmium hydroxide reacted with 15.21 g of hydrobromic acid. How many grams of water can be made?
Alecsey [184]

Answer:

m_{H_2O}=3.384gH_2O

Explanation:

Hello,

In this case, the chemical reaction is:

Cd(OH)_2+2HBr\rightarrow CdBr_2+2H_2O

Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:

n_{H_2O}^{by\ Cd(OH)_2}=19.3gCd(OH)_2*\frac{1molCd(OH)_2}{146.4gCd(OH)_2}*\frac{2molH_2O}{1molCd(OH)_2}=0.264molH_2O\\\\n_{H_2O}^{by\ HBr}=15.21gHBr*\frac{1molHBr}{80.9gHBr}*\frac{2molH_2O}{2molHBr}=0.188molH_2O

In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:

m_{H_2O}=0.188molH_2O*\frac{18gH_2O}{1molH_2O}\\ \\m_{H_2O}=3.384gH_2O

Regards.

4 0
3 years ago
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