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USPshnik [31]
3 years ago
8

Balance Cr2O3+Mg -->Cr + MgO

Chemistry
1 answer:
fiasKO [112]3 years ago
6 0

Balancing means there are equal amount of molecules on each side, both reactant and products. This is a method I like to do.

Under, I count how many molecules are in each side.

              Cr2O3+Mg -->Cr + MgO

Cr:              2                    1

O:                     3                            1

Mg:                         1                 1

Let's guess and make the number of oxygens equal on both sides.

              Cr2O3+Mg -->Cr + 3MgO

Cr:             2                    1

O:                      3                           3       EQUAL

Mg:                          1                   3

See what we did there? We multiplied the MgO on the products side by 3 so we can have 3 oxygens. Now let's multiply the Mg on the reactants by three so Mg AND O can be equal.

                Cr2O3+3Mg -->Cr + 3 MgO

Cr:              2                      1

O:                      3                               3        EQUAL

Mg:                         3                        3          EQUAL

Finally, we just need to multiply the loner Cr in the products side by two to make it equal for all elements.

                 Cr2O3+3Mg -->2Cr + 3 MgO

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<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

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PV=\frac{m}{M}RT

where,

P = pressure of container = 200 kPa

V = volume of container = ? L

m = Given mass of water = 2.61 kg = 2610 g   (Conversion factor: 1kg = 1000 g)

M = Molar mass of water = 18 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 200^oC=[200+273]K=473K

Putting values in above equation, we get:

200kPa\times V=\frac{2610g}{18g/mol}\times 8.31\text{L kPa }\times 473K\\\\V=2849.7L

Converting this into cubic meter, we use the conversion factor:

1m^3=1000L

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