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3 years ago

How do scientists define matter

Physics

2 answers:

melisa1 [442]3 years ago

8 0

Scientists define matter as anything that has mass.

KatRina [158]3 years ago

4 0

Anything that is made up of atoms.

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When an unbalanced force acts on an object the change in the objects ____or ____ depends on the size and direction of the force

timama [110]

When an unbalanced force acts on an object the change in the object state of rest or motion depends on the size and direction of the force.

If a body is at state of rest or motion, when an unbalanced external force acts on it, its starts moving in the direction of force and magnitude of its velocity or acceleration depends on the magnitude of force applied.

7 0

3 years ago

Read 2 more answers

I. Choose the correct answer:

Ann [662]

Answer:

1. c

2. b

3. a

4. a

5. a

6. a

7. d

8. b

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3 years ago

A person is standing on the beach counting the waves that come in. The person counts 10.0 waves in 68.0 s. What is the frequency

worty [1.4K]

Answer: 0.14 Hz

Explanation:

We are told the person counts 10 waves in 68 s, from this information we can calculate the frequency $f$ , which is defined as the number of oscilations or waves per unit of time. Then:

$f=\frac{10 waves}{68 s}$

$f=0.14 s^{-1}$

This is the frequency of the ocean waves. Now, according to the International System of Units (SI), frequency is measured in Hertz ( $Hz$ ), which is equivalent to $s^{-1}$ .

So, according to this, the frequency of the ocean waves is $f=0.14 Hz$

3 0

3 years ago

Any help guys? I am stuck on two problems.

Juli2301 [7.4K]

Ax=A*Cos56

= 20*(0.559)

= 11.18 N

8 0

3 years ago

A 10kg ball moving at 9.0 m/s strikes a stationary 130kg man on the chest after which the ball bounces back at 5.0 m/s What is t

julsineya [31]

We know that

• The mass of the ball is 10kg.

• The initial velocity of the ball is 9m/s.

• The mass of the man is 130kg.

• The initial velocity of the man is null (stationary).

• The final velocity of the ball is 5m/s.

To find the final velocity of the person, we have to use the law of conservation of momentum.

$p_i=p_f$

Where p = mv. Using all the given information, we have

$\begin{gathered} m_{^{}_{ball}}v_{i_{ball}}+m_{_{man}}v_{i_{man}}=m_{\text{ball}}v_{f_{ball}}+m_{man}v_{f_{man}}_{} \\ 10\operatorname{kg}\cdot9m/s+130\operatorname{kg}\cdot0=10\operatorname{kg}\cdot5m/s_{}_{}+130\operatorname{kg}\cdot v_{f_{man}} \end{gathered}$

Then, we solve for v

$\begin{gathered} 90\operatorname{kg}\cdot m/s=50\operatorname{kg}\cdot m/s+130\operatorname{kg}\cdot v_{f_{man}} \\ \frac{90\operatorname{kg}\cdot m/s-50\operatorname{kg}\cdot m/s}{130\operatorname{kg}}=v_{f_{man}} \\ v_{f_{man}}=\frac{40\operatorname{kg}\cdot m/s}{130\operatorname{kg}}\approx0.31m/s \end{gathered}$ <h2>Therefore, the velocity of the person after the ball bounces off him is 0.31 meters per second, approximately.</h2>

4 0

1 year ago