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3 years ago

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Electrons with energy of 25 eV have a wavelength of ~0.25 nm. If we send these electrons through the same two slits (d = 0.16 mm

) we use to produce a visible light interference pattern what is the spacing (in micrometer) between maxima on a screen 3.3 m away?

1 answer:

kupik [55]3 years ago

7 0

Answer:

The spacing is 5.15 μm.

Explanation:

Given that,

Electron with energy = 25 eV

Wave length = 0.25 nm

Separation d= 0.16 mm

Distance D=3.3 m

We need to calculate the spacing

Using formula of width

$\beta=\dfrac{\lambda D}{d}$

Put the value into the formula

$\beta=\dfrac{0.25\times10^{-9}\times3.3}{0.16\times10^{-3}}$

$\beta=5.15\times10^{-6}\ m$

$\beta=5.15\ \mu m$

Hence, The spacing is 5.15 μm.

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$E_{m} = 169.2 J + 0 = 169.2 J$

I hope it helps you!

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