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Yanka [14]
3 years ago
6

Electrons with energy of 25 eV have a wavelength of ~0.25 nm. If we send these electrons through the same two slits (d = 0.16 mm

) we use to produce a visible light interference pattern what is the spacing (in micrometer) between maxima on a screen 3.3 m away?
Physics
1 answer:
kupik [55]3 years ago
7 0

Answer:

The spacing is 5.15 μm.

Explanation:

Given that,

Electron with energy = 25 eV

Wave length = 0.25 nm

Separation d= 0.16 mm

Distance D=3.3 m

We need to calculate the spacing

Using formula of width

\beta=\dfrac{\lambda D}{d}

Put the value into the formula

\beta=\dfrac{0.25\times10^{-9}\times3.3}{0.16\times10^{-3}}

\beta=5.15\times10^{-6}\ m

\beta=5.15\ \mu m

Hence, The spacing is 5.15 μm.

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A residential subdivision encompasses 1100 acres with a housing density of four houses per acre. Assume that a high-value reside
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Answer:

(a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

Explanation:

Given that,

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Number of house in 1 acres = 4

\text{Number of house in 1100 acres} = 4\times1100

\text{Number of house in 1100 acres} = 4400

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Using formula for average daily demand

\text{average daily demand}=house\times\text{Per house water demand}

\text{average daily demand}=4400\times800\ gallon/day

\text{average daily demand}=3520000\ gallon/day

\text{average daily demand}=\dfrac{3520000}{24\times60}\ gallon/min

\text{average daily demand}=2444.44\ gallon/min

The average daily demand of this subdivision is 2444.44 gallon/min.

(b). We need to calculate the design-demand used to design the distribution system

Using formula for the design-demand

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\text{design demand}=1.64\times2444.4\times1000

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(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

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Solving for v, we find the speed of the projectile:

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