1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
astra-53 [7]
3 years ago
15

Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

he first having a mass of 150,000 kg and a velocity of 0.300 m/s, and the second having a mass of 95,000 kg and a velocity of -0.120 m/s. (The minus indicates direction of motion.) What is their final velocity?
Physics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:   0.137 m/s

Explanation:

from the question we are given the following

mass of train A (Ma) = 150,000 kg

velocity of train A (Va) = 0.3 m/s

mass of train B (Mb) = 95,000 kg

velocity of train B (Vb) = -0.12 m/s

final velocity (V) = ?

mass of both trains = 245,000 kg

  • to solve this question we apply the conservation of momentum

MaVa + MbVb = (Ma + Mb) x V

V = (MaVa + MbVb) /  (Ma + Mb)

V =  ((150,000 x 0.3) + (95,000 x (-0.12))) /  (245,000)

V = -33600 / 245,000

V = 0.137 m/s

You might be interested in
Describe the electromagnetic spectrum, electromagnetic waves, and give two examples of different types of electromagnetic waves.
Alex

Answer:

Radio Wave

Micro Wave

Explanation:

Electromagnetic waves are transverse waves composed by the perpendicular oscillating electric and magnetic fields.

EM waves have both Electrical and magnetic features.

they travel in the velocity of light (3*10⁸ ms⁻¹)

Electromagnetic spectrum is obtained according to their wave length and the frequency. Due to wave length range it's categorized. Here is the decreasing  order of wave length and increasing order  of different wave types in electromagnetic spectrum

  • Radio Wave
  • Micro Wave
  • IR wave
  • Light Wave
  • UV rays
  • X rays
  • Gamma rays
  • Cosmic rays

5 0
3 years ago
Un neumático sin cámara, soporta una presión de 1.5 atm cuando la temperatura ambiente es de 300°K. ¿Qué presión llegará a sopor
arlik [135]

Answer:

El neumático soportará una presión de 1.7 atm.

Explanation:

Podemos encontrar la presión final del neumático usando la ecuación del gas ideal:

PV = nRT

En donde:

P: es la presión

V: es el volumen

n: es el número de moles del gas

R: es la constante de gases ideales

T: es la temperatura

Cuando el neumático soporta la presión inicial tenemos:

P₁ = 1.5 atm

T₁ = 300 K

V_{1} = \frac{nRT_{1}}{P_{1}}  (1)  

La presión cuando T = 67 °C es:

P_{2} = \frac{nRT_{2}}{V_{2}}   (2)

Dado que V₁ = V₂  (el volumen del neumático no cambia), al introducir la ecuación (1) en la ecuación (2) podemos encontrar la presión final:

P_{2} = \frac{nRT_{2}}{V_{2}} = \frac{nRT_{2}}{\frac{nRT_{1}}{P_{1}}} = \frac{P_{1}T_{2}}{T_{1}} = \frac{1.5 atm*(67 + 273)K}{300 K} = 1.7 atm  

Por lo tanto, si en el transcurso de un viaje las ruedas alcanzan una temperatura de 67 ºC, el neumático soportará una presión de 1.7 atm.

Espero que te sea de utilidad!

4 0
3 years ago
10,500 J of GPE, weight 539 N, how tall is the hill you are sitting on?
maks197457 [2]

Answer:

19.48 m

Explanation:

Gravitational potential energy = mgh

Current weight = 539 N

Weight = mg = 539 N

Mass x Acceleration = 539 N

Mass x 9.81 = 539

Mass = 54.94 kg

Gravitational potential energy = mgh = 10500 J

                    54.94 x 9.81 x h = 10500

                               h = 19.48 m

Height of sitting = 19.48 m

6 0
3 years ago
The doppler effect is used to determine?
Korolek [52]
Uhh it is used to detirmine heat

7 0
3 years ago
Read 2 more answers
20. Consider a model steel bridge that is 1/100 the exact scale of the real bridge that is to be built. a. If the model bridge w
Veseljchak [2.6K]
The model bridge captures all the structural attributes of the real bridge, at a reduced scale.

Part a.
Note that volume is proportional to the cube of length. Therefore the actual bridge will have 100^3 = 10^6 times the mass of the model bridge.

Because the model bridge weighs 50 N, the real bridge weighs
(50 N)*10^6 = 50 MN.

Part b.
The model bridge matches the structural characteristics of the actual bridge.
Therefore the real bridge will not sag either.
6 0
3 years ago
Other questions:
  • WHAT IS THE KE OF 2KG BALL AT SPEED 5M/S AT 40M TALL?
    14·1 answer
  • sky divers jump out of planes at an altitude of 4000m. How much timewill passuntill they deploy their parachutes at an altitutde
    12·1 answer
  • The terminal speed of a sky diver is 130 km/h in the spread-eagle position and 326 km/h in the nosedive position. Assuming that
    15·1 answer
  • What would happen to the moon if the earth stopped exerting the force of gravity onto it?
    6·1 answer
  • A light bulb is left on for an hour and has a power of 0.1KW. How much did it cost?
    12·1 answer
  • How often do the earth's magnetic poles switch?
    5·1 answer
  • Which statement best describes the main idea of the poem
    6·1 answer
  • A car is moving north on a freeway. If a bug is flying south on the freeway, is the momentum of the bug positive or negative?
    14·1 answer
  • Does increase in metabolism accelerates weight loss?.
    12·1 answer
  • What is the 3 word definition for momentum?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!