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astra-53 [7]
3 years ago
15

Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

he first having a mass of 150,000 kg and a velocity of 0.300 m/s, and the second having a mass of 95,000 kg and a velocity of -0.120 m/s. (The minus indicates direction of motion.) What is their final velocity?
Physics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:   0.137 m/s

Explanation:

from the question we are given the following

mass of train A (Ma) = 150,000 kg

velocity of train A (Va) = 0.3 m/s

mass of train B (Mb) = 95,000 kg

velocity of train B (Vb) = -0.12 m/s

final velocity (V) = ?

mass of both trains = 245,000 kg

  • to solve this question we apply the conservation of momentum

MaVa + MbVb = (Ma + Mb) x V

V = (MaVa + MbVb) /  (Ma + Mb)

V =  ((150,000 x 0.3) + (95,000 x (-0.12))) /  (245,000)

V = -33600 / 245,000

V = 0.137 m/s

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8 0
3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu
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Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6.8 \times  {5}^{2}

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8 0
4 years ago
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Answer: 347 bar


Explanation:

1) Data:


n = 2520 moles

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V = 180 liter

p = ?


2) Formula


Ideal gas equation: pV = nRT


3) Solution:


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Conversion: 342.7 atm × 1,01325 bar / atm = 347 bar



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3 years ago
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