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Lynna [10]
3 years ago
15

Which part of the diagram represents the proton

Physics
2 answers:
blsea [12.9K]3 years ago
7 0

Answer:

C

Explanation:

An atom consists essentially of three types of particles:

- Protons: these are contained in the nucleus, and they are positively charged

- Neutrons: this are also contained in the nucleus, but they have no electric charge

- Electrons: they orbit around the nucleus, and they have negative charge

Based on this diagram, we see that the particle labeled by C is a proton, since it is in the nucleus and it is positively charged. The particle labeled by B is a neutron, while the particle labeled by A is an electron.

Alexandra [31]3 years ago
6 0
Protons have a positive charge which is indicated by a + sign.
Hence, the answer is C.
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10. In Freudian theory, which one of the following is an example of a Thanatos instinct, which includes aggression, trauma, and
Lelechka [254]
D substance abuse :) hope this helps
8 0
2 years ago
Which of the following circuits will stop producing light if one bulb burns out? *
gulaghasi [49]

Answer:

Circuit 1 and Circuit 3

Explanation:

If there is 1 Circuit and it runs out of energy, there's another one to produce the power.

6 0
3 years ago
3, A 4kg block is pushed 2m at an acceleration of 0.2m/s square up a vertical wall by a constant force F applied at an angle of
Andrews [41]

The work done by the applied force on the block against the frictional force is 15.75 J.

<h3>Work done by the applied force</h3>

The work done by the applied force is calculated as follows;

W = Fd

F - Ff = ma

where;

  • F is applied force
  • Ff is frictional force

Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

0.799F - 7.077 = 0.8

F = 9.86 N

W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

Learn more about work done here: brainly.com/question/25573309

#SPJ1

5 0
2 years ago
Three joggers are running along straight lines as follows: Jogger A, with a mass of 55.2kg, is traveling along the line y=6.00m
frutty [35]

Answer:

L = - 1361.591 k Kgm/s

Explanation:

Given

mA = 55.2 Kg

vA = 3.45 m/s

rA = 6.00 m

mB = 62.4 Kg

vB = 4.23 m/s

rB = 3.00 m

mC = 72.1 Kg

vC = 4.75 m/s

rC = - 5.00 m

then we apply the equation

L =  (mv x r)

⇒  LA = mA*vA x rA = 55.2 *(3.45 i)x(6 j) = (1142.64 k) Kgm/s

⇒  LB = mB*vB x rB = 62.4 *(4.23 j)x(3 i) = (- 791.856 k) Kgm/s

⇒  LC = mC*vC x rC = 72.1 *(- 4.75 j)x(- 5 i) = (- 1712.375 k) Kgm/s

Finally, the total counterclockwise angular momentum of the three joggers about the origin is

L = LA + LB + LC = (1142.64 - 791.856 -1712.375) k  Kgm/s

L = - 1361.591 k Kgm/s

7 0
3 years ago
Why wil an ice cube melt if it is compressed even if it remains at the same temp
Gnoma [55]
No, it will only melt if the temperature is lowered. If you compress it, it will change the shape, but it will not change the state it is in (i.e. solid).
8 0
3 years ago
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