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Thepotemich [5.8K]
4 years ago
5

When placed in a lake, an object either floats on the surface or sinks. It does not float at some intermediate location between

the surface and the bottom of the lake. However, a weather balloon floats at some intermediate distance between Earth's surface and the top of its atmosphere. Explain.
Physics
2 answers:
STALIN [3.7K]4 years ago
3 0
The particle in the air match the mass with the particles around the balloon stoping it from floating any higher
Gnoma [55]4 years ago
3 0

Explanation:

i get your your qiestion but i am not trying to be annoying so please what is a wheather ballon

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Which statements describe a closed circuit? Check all that apply. Bulbs will shine. Bulbs will not shine. The circuit is incompl
vaieri [72.5K]

Bulbs will shine.

The circuit is complete.

Charges flow.

4 0
3 years ago
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As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh
marshall27 [118]

Answer:

The resultant velocity is  v_t=10 knots

Explanation:

Apply the law of conservation of momentum

     M_L *v_L + M_f * V_f = (M_L + M_f) v_t

Where M_L is the mass of the Luxury Liner = 40,000 ton

            v_L is the velocity of Luxury Liner = 20 knots due west

            M_f mass of freighter = 60,000

           v_f is the velocity of freighter = 10 knots due north

Apply the law of conservation of momentum toward the the west direction

         v_f = 0 \ knots

So the equation would be

              M_L *v_L = (M_L + M_f) v_t

Substituting values

            40000*20 = (40000+ 60000)v_t_w

Where v_t_w the final velocity due west

Making v_t_w the subject

          v_t_w = \frac{40,000* 20}{(40000 + 60000)}

                = 8 \ knots

Apply the law of conservation of momentum toward the the north direction          

          v_L = 0 \ knots

So the equation would be

           M_f *v_f = (M_L + M_f) v_t_n

Where v_t_n the final velocity due north

     Making v_t_n the subject

          v_t_n = \frac{60,000* 10}{(40000 + 60000)}

                = 6 \ knots

The resultant velocity is

       v_t = \sqrt{v_t_w^2 + v_t_n^2}

            = \sqrt{8^2 +6^2}

           v_t=10 knots

8 0
3 years ago
What acceleration will all objects experience during their flights through the air (on Earth)?
Salsk061 [2.6K]

Answer:

d

Explanation:

4 0
3 years ago
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14*3(36/2(1*3)/6<br><img src="https://tex.z-dn.net/?f=14%20%5Ctimes%203%2836%20%5Cdiv%202%281%20%5Ctimes%203%29%20%5Cdiv%206" id
GarryVolchara [31]
<h2>10.5</h2><h3>remember pemdas</h3>
  • parentheses
  • exponents <em>excluded for this problem</em>
  • multiplication
  • division
  • addition
  • subtraction
<h3>step 1. start with what is at the top of the list.</h3>
  • parentheses
<h3>step 2. do 1 times 3 since it comes before division, and is in parentheses.</h3>

1 × 3 = 3

<h3>step 3. find 36 divided by 2</h3>

36 ÷ 2 = 18

<h3>step 4. add the values together</h3>

18 + 3 = 21

<h3>step 5. find 14 times 3</h3>

14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>

<h3>step 6. add what is outside the parentheses</h3>

21 + 42 = 63

<h3>step 7. divide by 6</h3>

63 ÷ 6 = 10.5 -- > 10 remainder of 3 <em>remainder means left over</em>

<em />

7 0
2 years ago
The magnetic field at the centre of a toroid is 2.2-mT. If the toroid carries a current of 9.6 A and has 6.000 turns, what is th
ziro4ka [17]

Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, B=2\ mT=2.2\times 10^{-3}\ T

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :                  

B=\dfrac{\mu_oNI}{2\pi r}

r=\dfrac{\mu_oNI}{2\pi B}  

r=\dfrac{4\pi \times 10^{-7}\times 6\times 9.6}{2.2\pi \times 2\times 10^{-3}}  

r = 0.00523 m

or

r=5.23\times 10^{-3}\ m

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
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