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algol13
3 years ago
12

Which source is most likely an authority on the subject? Dr. Vale, a pediatrician, discusses electrical circuitry on her home-im

provement website. Jonah, an amateur cook, teaches his son how to make the best grilled cheese sandwiches. Susan, an architect, presents her hand-made quilts at the Quilting Society. Dr. Patel, a cardiologist, presents her findings on heart disease.
Physics
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer:

D.

Explanation:

I took the quiz

Naddika [18.5K]3 years ago
6 0
The correct answer is Dr. Patel, a cardiologist, presents her findings on heart disease.

A cardiologist is a heart doctor, so he would be the highest authority to speak about heart disease. The others are all amateurs in their businesses.
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3 years ago
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In separate experiments, a large number of particles (all with the same charge, but with a wide variety of masses and speeds) ar
likoan [24]

Answer:

  they have the same mass

Explanation:

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3 years ago
two object gravitationally attract with a force of 20N.if the distance between the two object centers is doubled, then what is t
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Gravity decreases with the square of the distance, so the new force is (20)/(2*2) = 5N.
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3 years ago
A laser with a power of 1.0 mW has a beam radius of 1.0 mm. What is the peak value of the electric field in that beam
Fynjy0 [20]

Answer:

The peak value of the electric field is 489.64 V/m

Explanation:

Given;

power of the laser, P = 1.0 mW = 1 x 10⁻³ W

Radius of the beam, R = 1.0 mm = 1 x 10⁻³ m

Area of the beam = πr² = π(1 x 10⁻³ )² = 3.142 x 10⁻⁶ m²

The average intensity of the light = P / A

The average intensity of the light = ( 1 x 10⁻³) / (3.142 x 10⁻⁶)

The average intensity of the light = 318.27 W/m²

The peak value of the electric field is given by;

E_o = \sqrt{\frac{2I_{avg}}{c\epsilon_o}}\\\\E_o = \sqrt{\frac{2(318.27)}{(3*10^8)(8.85*10^{-12})}}\\\\E_o = 489.64 \ V/m

Therefore, the peak value of the electric field is 489.64 V/m.

4 0
3 years ago
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:)

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3 years ago
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