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AlexFokin [52]
3 years ago
12

Please help,i really need this!!!

Chemistry
2 answers:
lana [24]3 years ago
6 0

Answer: Option (A) is the correct answer.

Explanation:

When calcium reacts with potassium chloride then  it results in the formation of calcium oxide and potassium ions.

The given equation is as follows.

     Ca(s) + KCl \rightarrow CaCl_{2}(s) + K^{+}

Number of atoms on reactant side are as follows.

  • Ca = 1
  • K = 1
  • Cl = 1

Number of atoms on product side are as follows.

  • Ca = 1
  • K = 1
  • Cl = 2

To balance the given equation, multiply KCl by 2 on the reactant side and multiply potassium ions by 2 on product side. Therefore, balanced chemical equation will be as follows.

        Ca(s) + 2KCl \rightarrow CaCl_{2}(s) + 2K^{+}

Makovka662 [10]3 years ago
5 0

A because KCL 2 and K + CL cancel out and Both of the Ca cancel each other out

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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

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Ray Of Light [21]
Answer: 2.60 x 10^23 molecules


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What is the name of this formula?
Alex_Xolod [135]

Answer:

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Explanation:

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