All categories

2 years ago

Nitrate has the formula \textit {NO}_\textit3^-NO

Chemistry

1 answer:

stellarik [79]2 years ago

4 0

The formula for Nitrate is NO3-

You might be interested in

What is the only thing that changes in a chemical reaction

kirill [66]

Bbbbbbbbbbbbbbbbbbbbb

3 0

3 years ago

2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g

Gemiola [76]

Answer:

volume of $H_2=33.6 litre$

Explanation:

Firstly balance the given chemical equation,

$2Li + H_2SO_4=Li_2SO_4 + H_2$

From the given balance equation it is clearly that,

2 mole of Li gives 1 mole of H2 gas

$2 mole Li$ ⇔ $1 mole H_2$

$1 mole Li$ ⇔ $0.5 mole H_2$

$3 mole Li$ ⇔ $1.5 mole H_2$

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at $STP = 1.5\times22.4 \frac{L}{mol}$

volume of H2=33.6 litre

7 0

3 years ago

The shells further away from the nucleus are larger/smaller and can hold more/less electrons.

Sergeu [11.5K]

The shells further away from the nucleus are LARGER and can hold MORE electrons

8 0

2 years ago

The radius of a potassium atom is 231 pm. How many potassium atoms would have to be laid side by side to span a distance of 4.77

Softa [21]

To determine the number of potassium laid side by side by a given distance, we simply divide the total distance to the diameter of each atom. The diameter is twice the radius of the atom. We calculate as follows:

number of atoms = 4770 / 231x10^-12 = 2.06x10^13 atoms

3 0

3 years ago

Read 2 more answers

Be sure to answer all parts. Sulfur dioxide is released in the combustion of coal. Scrubbers use lime slurries of calcium hydrox

scoray [572]

<u>Answer:</u> The balanced chemical equation is written below and $\Delta S^o$ for the reaction is -160.6 J/K

<u>Explanation:</u>

When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.

The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

$Ca(OH)_2(s)+SO_2(g)\rightarrow CaSO_3(s)+H_2O(l)$

To calculate the entropy change of the reaction, we use the equation:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]$

For the given reaction:

$\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]$

Taking the standard entropy change values:

$\Delta S^o_{CaSO_3(s)}=101.4Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O(l)}=69.9Jmol^{-1}K^{-1}\\\Delta S^o_{Ca(OH)_2(s)}=83.4Jmol^{-1}K^{-1}\\\Delta S^o_{SO_2(g)}=248.5Jmol^{-1}K^{-1}$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K$

Hence, the balanced chemical equation is written above and $\Delta S^o$ for the reaction is -160.6 J/K

3 0

3 years ago