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Nostrana [21]
3 years ago
6

The equation, H2SO4 (aq) + Sr(OH)2 (aq) arrow SrSO4 (aq) + H2O (l), represents what?

Chemistry
2 answers:
larisa [96]3 years ago
7 0
I think the correct answer from the choices listed above is the second option. <span>The equation, H2SO4 (aq) + Sr(OH)2 (aq) ----> SrSO4 (aq) + H2O (l), represents </span><span>overall equation for a strong acid-strong base neutralization reaction. Hope this answers the question. Have a nice day.
</span>
hichkok12 [17]3 years ago
6 0

<u>Answer:</u> The correct answer is overall equation for a strong acid-strong base neutralization reaction.

<u>Explanation:</u>

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

Strong acid is defined as the acid which gets completely dissociated into its ions when dissolved in water. For Example: H_2SO_4 etc..

Weak acid is defined as the acid which does not get completely dissociated into its ions when dissolved in water. For Example: HCOOH etc..

Strong base is defined as the base which gets completely dissociated into its ions when dissolved in water. For Example: NaOH etc..

Weak base is defined as the base which does not get completely dissociated into its ions when dissolved in water. For Example: NH_4OH etc..

For the given chemical reaction:

H_2SO_4(aq.)+Sr(OH)_2(aq.)\rightarrow SrSO_4(aq.)+H_2O(l)

Here, H_2SO_4 is a strong acid and Sr(OH)_2 is a strong base. So, the salt produced by these two will be a neutral salt and their reaction will be a strong acid-strong base neutralization.

Hence, the correct answer is overall equation for a strong acid-strong base neutralization reaction.

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CaCO3 → CaO + CO2 Calculate the theoretical yield of Calcium Oxide if 24.8 grams of Calcium Carbonate decomposes. Calculate the
RideAnS [48]

Answer:

Theoretical yield: 13.9 g

Percent yield: 94 %

Explanation:

The reaction is:

CaCO₃ → CaO + CO₂

We see that the reaction is correctly balanced.

1 mol of calcium carbonate can decompose to 1 mol of calcium oxide and 1 mol of carbon dioxide.

We convert the mass to moles: 24.8 g . 1mol / 100.08g = 0.248 moles

As ratio is 1:1, 0.248 moles of salt can decompose to 1 mol of oxide.

We convert the moles to mass: 0.248 mol . 56.08g /1mol = 13.9 g

That's the theoretical yield.

To determine the percent yield we think:

(Determined yield / Theoretical yield) . 100 → (13.1 / 13.9) . 100 = 94 %

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