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Nostrana [21]
3 years ago
6

The equation, H2SO4 (aq) + Sr(OH)2 (aq) arrow SrSO4 (aq) + H2O (l), represents what?

Chemistry
2 answers:
larisa [96]3 years ago
7 0
I think the correct answer from the choices listed above is the second option. <span>The equation, H2SO4 (aq) + Sr(OH)2 (aq) ----> SrSO4 (aq) + H2O (l), represents </span><span>overall equation for a strong acid-strong base neutralization reaction. Hope this answers the question. Have a nice day.
</span>
hichkok12 [17]3 years ago
6 0

<u>Answer:</u> The correct answer is overall equation for a strong acid-strong base neutralization reaction.

<u>Explanation:</u>

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

Strong acid is defined as the acid which gets completely dissociated into its ions when dissolved in water. For Example: H_2SO_4 etc..

Weak acid is defined as the acid which does not get completely dissociated into its ions when dissolved in water. For Example: HCOOH etc..

Strong base is defined as the base which gets completely dissociated into its ions when dissolved in water. For Example: NaOH etc..

Weak base is defined as the base which does not get completely dissociated into its ions when dissolved in water. For Example: NH_4OH etc..

For the given chemical reaction:

H_2SO_4(aq.)+Sr(OH)_2(aq.)\rightarrow SrSO_4(aq.)+H_2O(l)

Here, H_2SO_4 is a strong acid and Sr(OH)_2 is a strong base. So, the salt produced by these two will be a neutral salt and their reaction will be a strong acid-strong base neutralization.

Hence, the correct answer is overall equation for a strong acid-strong base neutralization reaction.

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kvasek [131]

Answer:

Mass of sodium chloride decomposed = 24.54 g

Explanation:

Given data:

Mass of sodium chloride decomposed = ?

Mass of chlorine gas formed = 15 g

Solution:

Chemical equation:

2NaCl      →         2Na + Cl₂

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 15 g/ 71 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of Cl₂ with NaCl from balance chemical equation.

                    Cl₂            :              NaCl

                      1              :                2

                      0.21         :            2×0.21 = 0.42 mol

Mass of Sodium chloride decompose:

Mass = number of moles × molar mass

Mass = 0.42 mol × 58.44 g/mol

Mass = 24.54 g

4 0
3 years ago
What is insulin's structure?<br> a.quaternary<br> b.secondary<br> c.primary<br> d.tertiary
svetoff [14.1K]

Answer:

A

Explanation:

Quaternary structure of proteins is composed of two or more polypeptide chains. Insulin has two; one alpha  and one beta chain. The two chains are joined together by disulfide bonds at two points (at cysteines). Other examples of quaternary proteins structures are DNA polymerase and hemoglobin.

7 0
3 years ago
The lab procedure mentions that not all of the oxone may dissolve after being added to the water because the water may be satura
ollegr [7]

Answer:

The answer is (C) There are more solute molecules than water molecules.

Explanation:

A saturated solution is one in which no more solute can be dissolved or disintegrated into the solvent. When or if the ozone  stops being dissolved in the water, it implies that the water has already taken on more ozone molecules than it can contain, meaning there are more solute molecules (ozone molecules) than there are solvent molecules (water molecules).

3 0
3 years ago
Read 2 more answers
6.00 moles of sodium perchlorate contains the same number of atoms as __________. 6.00 moles of sodium perchlorate contains the
Ksju [112]

Answer:

6.00 moles of sodium permanganate

Explanation:

Let us attempt to count the number of atoms present in sodium perchlorate. The formula of the compound is NaClO4

Sodium atoms - 1

Chlorine atoms - 1

Oxygen atoms -4

Total number of atoms = 6

Among the options, only KMnO4 also has six atoms. One atom of potassium, one atom of manganese and four atoms of oxygen.

3 0
3 years ago
An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with
Kamila [148]

Answer:

The molar mass of the unknown acid is 89 g/mol

Explanation:

<u>Step 1:</u> The balanced equation

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

<u>Step 2:</u> Data given

Mass of the acid = 0.093 grams

volume = 250 mL

titrates with 0.16 M NaOH

adds 6.5 mL NaOH

<u>Step 3: </u>Calculate moles of NaOH

We know the concentration and volume of NaOH needed to neutralize the acid.

By determining the moles of NaOH in that volume in liters (95.9mL=0.0959L), the moles of acid in the original sample can be determined from the reaction stoichiometry.

Moles = Molarity * Volume

Moles = 0.16 M * 0.0065 L

Moles = 0.00104 moles NaOH

<u>Step 4: </u>Calculate moles of the unknown acid:

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

For 0.00104 moles NaOH we have 0.00104 moles of HA

<u>Step 5: </u>Calculate the molar mass of the acid

Molar mass Ha = Mass Ha / moles Ha

Molar mass Ha = 0.093 grams / 0.00104 moles

Molar mass Ha = 89.42 g/mol ≈89 g/mol

The molar mass of the unknown acid is 89 g/mol

3 0
3 years ago
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