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3 years ago

The equation, H2SO4 (aq) + Sr(OH)2 (aq) arrow SrSO4 (aq) + H2O (l), represents what?

2 answers:

7 0

I think the correct answer from the choices listed above is the second option. The equation, H2SO4 (aq) + Sr(OH)2 (aq) ----> SrSO4 (aq) + H2O (l), represents overall equation for a strong acid-strong base neutralization reaction. Hope this answers the question. Have a nice day.

hichkok12 [17]3 years ago

6 0

Answer: The correct answer is overall equation for a strong acid-strong base neutralization reaction.

Explanation:

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

Strong acid is defined as the acid which gets completely dissociated into its ions when dissolved in water. For Example: $H_2SO_4$ etc..

Weak acid is defined as the acid which does not get completely dissociated into its ions when dissolved in water. For Example: $HCOOH$ etc..

Strong base is defined as the base which gets completely dissociated into its ions when dissolved in water. For Example: $NaOH$ etc..

Weak base is defined as the base which does not get completely dissociated into its ions when dissolved in water. For Example: $NH_4OH$ etc..

For the given chemical reaction:

$H_2SO_4(aq.)+Sr(OH)_2(aq.)\rightarrow SrSO_4(aq.)+H_2O(l)$

Here, $H_2SO_4$ is a strong acid and $Sr(OH)_2$ is a strong base. So, the salt produced by these two will be a neutral salt and their reaction will be a strong acid-strong base neutralization.

Hence, the correct answer is overall equation for a strong acid-strong base neutralization reaction.

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A piece of silver metal has a mass of 3.687 grams. If the density of silver is 10.5 g/cm, what is the volume of the silver?

GenaCL600 [577]

Answer:

Volume = (0.62 m)^3

Explanation:

If the density of silver is 10.5 g/cm, the volume of the silver is (0.62 m)^3.

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2 years ago

Please show all of your work! :)

Paladinen [302]

Answer:

Explanation:

To answer this, we need to use Gay-Lussac's law, which states that:

$\frac{P_1}{T_1}= \frac{P_2}{T_2}$ , where P is pressure and T is temperature

The initial pressure we're given is 4.5 atm (so P1 = 4.5) and the temperature is 45.0°C; however, we need to change Celsius to Kelvins, so add 273 to 45.0: 45.0 + 273 = 318 K (so T1 = 318).

The final pressure is what we want to find, but we do know the final temperature is 3.1°C. Converting this to Kelvins, we get: 3.1 + 273 = 276.1 K, which means T2 = 276.1.

Plug these values in:

$\frac{P_1}{T_1}= \frac{P_2}{T_2}$

$\frac{4.5}{318}= \frac{P_2}{276.1}$

Multiply both sides by 276.1:

$P_2$ ≈ 3.9 atm

The answer is thus A.

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3 years ago

How many moles of hydrogen gas will be produced if 5.00 moles of zinc reactions with an excess amount of sulfuric acid

harkovskaia [24]

Answer:

Moles of Hydrogen produced is 5 moles

Explanation:

The balanced Chemical equation for reaction between zinc and sulfuric acid is :

$Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)$

This equation tells that ; when 1 mole of Zn react with 1 mole of sulfuric acid, it produces 1 mole of zinc sulfate and 1 mole of hydrogen.

Since sulfuric acid is in excess so Zinc is the limiting reagent

(Limiting reagent : Substance which get consumed when the reaction completes, limiting reagent helps in predicting the amount of products formed)

Limiting reagent (Zn) will decide the amount of Hydrogen produced

$Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)$

$1\ mole\ zinc\rightarrow 1\ mole\ H_{2}$

So,

$5\ mole\ zinc\rightarrow 5\ mole\ H_{2}$

Hence moles of Hydrogen produced is 5 moles

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3 years ago

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Damm [24]

Answer:

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The components of the electron transport chain are located in the internal part of the mitochondrial membrane in eukaryotic cells, and in the cell membrane in bacteria. The transporters in the electron transport chain are organized into four complexes in the inner mitochondrial membrane. A fifth complex then couples these reactions to the ATP synthesis.

Complex II receives the electrons from the succinate, which is an intermediary in the Krebs cycle. These electrons are transferred to the FADH₂ and then to the Q coenzyme. This liposoluble molecule will transport the electrons from Complex II to Complex III. In this complex, the electrons are transferred from the b cytochrome to the c cytochrome. This c cytochrome, which is a peripheric membrane protein located in the external part of the inner membrane, then transports the electrons to Complex IV where finally they are transferred to the oxygen.

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