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Nostrana [21]
3 years ago
6

The equation, H2SO4 (aq) + Sr(OH)2 (aq) arrow SrSO4 (aq) + H2O (l), represents what?

Chemistry
2 answers:
larisa [96]3 years ago
7 0
I think the correct answer from the choices listed above is the second option. <span>The equation, H2SO4 (aq) + Sr(OH)2 (aq) ----> SrSO4 (aq) + H2O (l), represents </span><span>overall equation for a strong acid-strong base neutralization reaction. Hope this answers the question. Have a nice day.
</span>
hichkok12 [17]3 years ago
6 0

<u>Answer:</u> The correct answer is overall equation for a strong acid-strong base neutralization reaction.

<u>Explanation:</u>

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

Strong acid is defined as the acid which gets completely dissociated into its ions when dissolved in water. For Example: H_2SO_4 etc..

Weak acid is defined as the acid which does not get completely dissociated into its ions when dissolved in water. For Example: HCOOH etc..

Strong base is defined as the base which gets completely dissociated into its ions when dissolved in water. For Example: NaOH etc..

Weak base is defined as the base which does not get completely dissociated into its ions when dissolved in water. For Example: NH_4OH etc..

For the given chemical reaction:

H_2SO_4(aq.)+Sr(OH)_2(aq.)\rightarrow SrSO_4(aq.)+H_2O(l)

Here, H_2SO_4 is a strong acid and Sr(OH)_2 is a strong base. So, the salt produced by these two will be a neutral salt and their reaction will be a strong acid-strong base neutralization.

Hence, the correct answer is overall equation for a strong acid-strong base neutralization reaction.

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Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

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Consider the balanced equation below.
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the balanced equation is as follows ;

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coefficients for the compounds in this reaction are as follows ;

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