A lens for a spotlight is coated so that it does not transmit yellow light. if the light sources is white, what color is the spo
1 answer:
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Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be = ..............1
put here value in equation 1
lowest frequency will be =
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength = ..............2
put here value
wavelength =
wavelength = 0.08575 m
so distance = ..............3
distance =
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
Answer:
a)
b)
Explanation:
The frequency of the harmonic of a vibrating string of length <em>L, </em>linear density
under a tension <em>T</em> is given by the formula:
a) So for the <em>fundamental mode</em> (n=1) we have, substituting our values:
b) The <em>frequency difference</em> between successive modes is the fundamental frequency, since: