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2 answers:
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The stopping distance is 143.1 m
Explanation:
First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:
where
is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)
m = 0.12 kg is the mass of the puck
a is the acceleration
Solving for a,
The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:
where:
v = 0 is the final velocity (the puck comes to a stop)
u = 18.3 m/s is the initial velocity
is the acceleration
s is the stopping distance
And solving for s, we find
Learn more about accelerated motion:
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