<span>sometimes you can see yourself as well, due to refraction and reflection
</span>
1. Which example best describes a restoring force?
B) the force applied to restore a spring to its original length
2. A spring is compressed, resulting in its displacement to the right. What happens to the spring when it is released?
C) The spring exerts a restoring force to the left and returns to its equilibrium position.
3. A 2-N force is applied to a spring, and there is displacement of 0.4 m. How much would the spring be displaced if a 5-N force was applied?
D) 1 m
4. Hooke’s law is described mathematically using the formula Fsp=−kx. Which statement is correct about the spring force, Fsp?
D)It is a vector quantity.
5. What happens to the displacement vector when the spring constant has a higher value and the applied force remains constant?
A) It decreases in magnatude.
Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:
You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:
hence, the speed of the Hubble is approximately 384km/min
To solve this problem we will use the mathematical definition of the light years in metric terms, from there, through the kinematic equations of motion we will find the distance traveled as a function of the speed in proportion to the elapsed time. Therefore we have to
means Light Year
Then
If we have that
Where,
v = Velocity
x = Displacement
t = Time
We have that
= Speed of light
Therefore will take 14.399 years
Answer:
Explanation:
Given that,
The absolute pressure inside the champagne is 6 times atmospheric pressure
Atmospheric pressure is 101,325 N/m²
So, the absolute pressure in the champagne is
P_abs = 6 × P_atm
P_abs = 6 × 101,325
P_abs = 607,950 N/m²
If the cork of the champagne has a mass of
M = 7.5g
M = 7.5 / 1000 = 0.0075 kg
The diameter of the cork is 18mm, It is no possible for the diameter to be 18m, so I assumed it is 18mm
d = 18mm = 0.018m
The area of the circle will be
Area = πd² / 4
Area = π × 0.018² / 4
Area = 2.545 × 10^-4 m²
We know that,
Pressure = Force / Area
Then,
Force = Pressure × Area
Force = 607,950 × 2.545 × 10^-4
Force = 154.723 N
Then, from newton second law,
F = ma
a = F / m
a = 154.723 / 0.0075
a = 20629.77 m/s²
a ≈ 20,630 m/s²
The acceleration of the cork is 20,630 m/s²
