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densk [106]
3 years ago
15

EMERGENCY 11??? DUE TOMORROW

Mathematics
2 answers:
poizon [28]3 years ago
8 0

First, we plug in the numbers.

$40 = P(4%)(2)

4% = 0.04

40 = P * 0.04 * 2

Divide each side by 2

20 = P * 0.04

Divide by 0.04

P = 500

Lets check it!

500 * 0.04 * 2 = 40

500 * 0.04 = 20

20 * 2 = 40

40 = 40

Triss [41]3 years ago
4 0

Answer:

a. I/rt= P

b. $500

Step-by-step explanation:

A.  I=Prt

divide both sides by rt

I/rt= P

B.

I/rt= P

40/(.04*2) =P

40/.08 = P

500=P

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$ 14.00

Step-by-step explanation:

10 · 1.75 = 17.50

17.50 · .20 = 3.5

17.50 - 3.50 = 14.00

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How many solutions does the following system have?<br> 2x- 4y = 11<br> -2x + 4y = -10
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Step-by-step explanation:

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Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
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