37.6*9.25=$<span>347.8 without deductions</span>
Answer:
The answer is
<h2>
</h2>
Step-by-step explanation:
The midpoint M of two endpoints of a given line segment can be found by using the formula
<h3>
</h3>
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(-4, -9), (-6, -6)
The midpoint is
<h3>
</h3>
We have the final answer as
<h3>
</h3>
Hope this helps you
Throughout all of these steps I'm only going to alter the left hand side (LHS). I am NOT going to change the right hand side (RHS) at all.
Before I change the LHS of the original equation, let's focus on the given identity
cot^2(x) + 1 = csc^2(x)
Since we know it's an identity, we can subtract 1 from both sides and the identity would still hold true
cot^2(x) + 1 = csc^2(x)
cot^2(x) + 1-1 = csc^2(x)-1
cot^2(x) + 0 = csc^2(x)-1
cot^2(x) = csc^2(x)-1
So we'll use the identity cot^2(x) = csc^2(x)-1
---------------------------------------------
Now onto the main equation given
cot^2(x) + csc^2(x) = 2csc^2(x) - 1
cot^2(x) + csc^2(x) = 2csc^2(x) - 1 .... note the term in bold
csc^2(x)-1 + csc^2(x) = 2csc^2(x) - 1 .... note the terms in bold
[ csc^2(x) + csc^2(x) ] - 1 = 2csc^2(x) - 1
[ 2csc^2(x) ] - 1 = 2csc^2(x) - 1
2csc^2(x) - 1 = 2csc^2(x) - 1
The bold terms indicate how the replacements occur.
So the original equation has been proven to be an identity because the LHS has been altered to transform into the RHS
Answer: 63.59cm²
Step-by-step explanation:
The area covered by the pitch will be gotten by finding the value of the area of the circle and this will be:
Area of q circle = πr²
where,
π = 3.14
r = radius = diameter/2 = 9cm/2 = 4.5cm
Area = πr² = 3.14 × 4.5²
= 3.14 × 20.25
= 63.59cm²
Therefore, the area covered by the pitch is 63.59cm²
