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zimovet [89]
3 years ago
11

Help ME PLEASE !9 POINTS !!!

Mathematics
2 answers:
algol133 years ago
5 0

Answer:

5x7x6= 210

Step-by-step explanation:

irina1246 [14]3 years ago
3 0

Answer:

the area is 36

Step-by-step explanation:

use (a+b/2)h

or use google lol

(5+7/2)6 - numbers in formula

(12/2)6 - parentheses

(6)6 - parentheses

36 - multiply

hope that helped

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Joan earns $9.25 per hour. She worked 37.6 hours last week. What was the amount of her check?
slava [35]
37.6*9.25=$<span>347.8  without deductions</span>
3 0
3 years ago
Read 2 more answers
Find the midpoint of the line segment with the given endpoints. 1) (-4, -9), (-6, -6)
weeeeeb [17]

Answer:

The answer is

<h2>( - 5 \: , \:  -  \frac{15}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, -9), (-6, -6)

The midpoint is

<h3>M = ( \frac{ - 4 - 6}{2}  , \:  \frac{ - 9 - 6}{2} ) \\  = ( -  \frac{10}{2} , -  \frac{15}{2} )</h3>

We have the final answer as

<h3>( - 5 \: , \:  -  \frac{15}{2} )</h3>

Hope this helps you

8 0
3 years ago
(Partially Done!) Verify the identity and show your work.
vladimir1956 [14]
Throughout all of these steps I'm only going to alter the left hand side (LHS). I am NOT going to change the right hand side (RHS) at all.

Before I change the LHS of the original equation, let's focus on the given identity
cot^2(x) + 1 = csc^2(x)

Since we know it's an identity, we can subtract 1 from both sides and the identity would still hold true
cot^2(x) + 1 = csc^2(x)
cot^2(x) + 1-1 = csc^2(x)-1
cot^2(x) + 0 = csc^2(x)-1
cot^2(x) = csc^2(x)-1

So we'll use the identity cot^2(x) = csc^2(x)-1

---------------------------------------------

Now onto the main equation given

cot^2(x) + csc^2(x) = 2csc^2(x) - 1
cot^2(x) + csc^2(x) = 2csc^2(x) - 1 .... note the term in bold
csc^2(x)-1 + csc^2(x) = 2csc^2(x) - 1 .... note the terms in bold
[ csc^2(x) + csc^2(x) ] - 1 = 2csc^2(x) - 1
[ 2csc^2(x) ] - 1 = 2csc^2(x) - 1
2csc^2(x) - 1 = 2csc^2(x) - 1

The bold terms indicate how the replacements occur.

So the original equation has been proven to be an identity because the LHS has been altered to transform into the RHS
7 0
3 years ago
A sports team is selling circular patches for their fans. Each patch has a
atroni [7]

Answer: 63.59cm²

Step-by-step explanation:

The area covered by the pitch will be gotten by finding the value of the area of the circle and this will be:

Area of q circle = πr²

where,

π = 3.14

r = radius = diameter/2 = 9cm/2 = 4.5cm

Area = πr² = 3.14 × 4.5²

= 3.14 × 20.25

= 63.59cm²

Therefore, the area covered by the pitch is 63.59cm²

4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!
FromTheMoon [43]
5 5/9 hope this helps :)
3 0
3 years ago
Read 2 more answers
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