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monitta
3 years ago
14

the distance formula is equivalent to the pythagorean theorem if you are trying to find the distance between a point in the plan

e and the orgin is this true or false???
Mathematics
2 answers:
anygoal [31]3 years ago
6 0

Let the point be (x,y) and the origin is (0,0).

Distance formula is

d = \sqrt{ (x_{2} - x_{1})^2 + ( y_{2} - y_{1})^2}

Substituting the points,we will get

d = \sqrt{ (0-x)^2 + (0-y)^2 }
\\
d = \sqrt{x^2 +y^2}

Squaring both sides

d^2 = x^2 + y^2
\\
x^2 + y^2 = d^2

And the pythagorean theorem is

a^2 +b^2 = c^2

And the above equation we obtained in in the form of pythagorea identity .

So the given statement is true .

user100 [1]3 years ago
5 0
The answer to this is true for apex

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Softa [21]

Answer:

Option C is correct

P(A or B) = 0.65

Step-by-step explanation:

<u>Given: </u>

P(A) =0.5

P(B)=0.30

P(A and B) =0.15

( The probability of the happening of both independent events will be there product) P( A and B ) =P(A).P(B)

<u>Solution:</u>

To find the probability  of the Happening of event A either event B  we will use the following formula

P(A or B) = P(A) + P(B)-P(A and B)

                  = 0.5 + 0.3 - 0.15

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3 years ago
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Step-by-step explanation:

this is the correct answer

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Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose
yawa3891 [41]

Answer:

V=5\sqrt{3}\ m^3

Step-by-step explanation:

we know that

The volume of a trough is equal to

V=BL

where

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step 1

Find the area of  equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

B=\frac{1}{2} b^{2} sin(60\°)

where

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sin(60\°)=\frac{\sqrt{3}}{2}

substitute

B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})

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step 2

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we have

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substitute

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V=5\sqrt{3}\ m^3

3 0
3 years ago
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