Answer:
C) formaldehyde, H2C=O.
Explanation:
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In this case, given that the hydrogen bondings are known as partial intermolecular interactions between a lone pair on an electron rich donor atom, particularly oxygen, and the antibonding molecular orbital of a bond between hydrogen and a more electronegative atom or group. Thus, among the options, C) formaldehyde, H2C=O, will exhibit hydrogen bonding since the lone pair of electrons of the oxygen at the carbonyl group, are able to interact with hydrogen (in the form of water).
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They are isotopes because isotopes have the same number of protons (atomic number) but can have different numbers of neutrons + protons (atomic mass).
Answer:
Approximately 
, assuming that this gas is an ideal gas.
Explanation:
Look up the standard room temperature and pressure:
and 
.
The question states that the volume of this gas is 
.
Convert the unit of all three measures to standard units:
.
.
.
Look up the ideal gas constant in the corresponding units: 
.
Let 
denote the number of moles of this gas in that . By the ideal gas law, if this gas is an ideal gas, then the following equation would hold:
.
Rearrange this equation and solve for :
.
In other words, there is approximately 
of this gas in that .
The ionization energy for a hydrogen atom in the n = 2 state is 328 kJ·mol⁻¹.
The <em>first ionization energy</em> of hydrogen is 1312.0 kJ·mol⁻¹.
Thus, H atoms in the <em>n</em> = 1 state have an energy of -1312.0 kJ·mol⁻¹ and an energy of 0 when <em>n</em> = ∞.
According to Bohr, Eₙ = k/<em>n</em>².
If <em>n</em> = 1, E₁= k/1² = k = -1312.0 kJ·mol⁻¹.
If <em>n</em> = 2, E₂ = k/2² = k/4 = (-1312.0 kJ·mol⁻¹)/4 = -328 kJ·mol⁻¹
∴ The ionization energy from <em>n</em> = 2 is 328 kJ·mol⁻¹
.
The answer is a. True. This is also known as the Le Chatelier's principle or The Equilibrium Law which states that if a chemical reaction is at equilibrium and then experiences changes in the condition of the reaction such as changes in concentration, pressure, or temperature of products or reactants, the system will naturally shift to achieve a new equilibrium state.
