Which of the following is the best example of an object in free fall?

Light is an example of something that travels in waves. Light waves come in many different varieties, and can be seen as many di

Anuta_ua [19.1K]

Answer:

Option (B)

Explanation:

Light is a form of electro-magnetic waves. This light wave has distinct range of wavelength that allows it to form different colors of light. This means that the color of the light produces depending on the amount of wavelength it comprises.

The visible light ranges from Violet to Red, and this is observed as different colors when each of these electromagnetic waves strikes our eyes at a certain angle. The violet light has the shortest wavelength of about 410 nm, where the red light has the highest wavelength of about 650 nm.

Thus, the correct answer is option (B).

6 0

3 years ago

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How is velocity different from speed?

enyata [817]

Velocity, unlike speed, includes a direction.

Velocity is a vector quantity which is defined by magnitude and direction.

Speed is a scalar quantity. It is the rate at which an object moves regardless of which direction.

5 0

3 years ago

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A ski jumper travels down a slope and leaves

Serhud [2]

Question seems to be missing. Found it on google:

a) How long is the ski jumper airborne?

b) Where does the ski jumper land on the incline?

a) 4.15 s

We start by noticing that:

- The horizontal motion of the skier is a uniform motion, with constant velocity

$v_x = 28 m/s$

and the distance covered along the horizontal direction in a time t is

$d_x = v_x t$

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity $u_y = 0$ and constant acceleration $g=9.8 m/s^2$ (where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

$d_y = \frac{1}{2}gt^2$

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is

$\theta = 36^{\circ}$ below the horizontal

This happens when:

$tan \theta = \frac{d_y}{d_x}$

Substituting and solving for t, we find:

$tan \theta = \frac{\frac{1}{2}gt^2}{v_x t}= \frac{gt}{2v_x}\\t = \frac{2v_x}{g}tan \theta = \frac{2(28)}{9.8} tan 36^{\circ} =4.15 s$

b) 143.6 m

Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:

$d_x = v_x t = (28)(4.15)=116.2 m$

$d_y = \frac{1}{2}gt^2 = \frac{1}{2}(9.8)(4.15)^2=84.4 m$

The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

$d=\sqrt{d_x^2+d_y^2}=\sqrt{(116.2)^+(84.4)^2}=143.6 m$

7 0

3 years ago

If you are doing a "rowing" motion, what muscle of the shoulder are you using?

Andrej [43]

The upper back muscles being worked while using a rowing machine .your upper trapezius and rhomboids located between your shoulder blades, and latissimus dorsi located beneath the armpits

6 0

3 years ago

How do I calculate equilibrant and fx and fy. I don't understand what they are asking

Natasha2012 [34]

(a) The equilibrant C for force of vector A and B is 3.43 N.

(b) The equilibrant C for fx of vector A and B is 2.1 N.

(c) The equilibrant C, for fy of vector A and B is 2.12 N.

<h3>What is equilibrant force?</h3>

An equilibrant force is a single force that will bring other bodies into equilibrium.

<h3>From configuration 1:</h3>

Vector A: mass = 0.2 kg, θ = 20⁰

Vector B: mass = 0.15 kg, θ = 80⁰

Fx = mg cosθ

Fy = mg sinθ

where;

m is mass
g is acceleration due to gravity

<h3>Vector A</h3>

Force of A due to its weight

F(A) = mg

F(A) = 0.2 x 9.8 = 1.96 N

Fx = (0.2 x 9.8) cos(20) = 1.84 N

Fy = (0.2 x 9.8) sin(20) = 0.67 N

<h3>Resultant force</h3>

R = √(0.67² + 1.84²)

R = 1.96 N

<h3>Vector B</h3>

Force of B due to its weight

F(B) = mg

F(B) = 0.15 x 9.8

F(B) = 1.47 N

Fx = (0.15 x 9.8) cos(80) = 0.26 N

Fy = (0.15 x 9.8) sin(80) = 1.45 N

<h3>Resultant force </h3>

R = √(0.26² + 1.45²)

R= 1.47 N

<h3>Equilibrant C of vector A and B</h3>

Equilibrant force:

Force, C = 1.96 N + 1.47 N

Force, C = 3.43 N

Equilibrant FX:

Fx, C = Fx(A) + Fx(B)

Fx, C = 1.84 N + 0.26 N = 2.1 N

Equilibrant FY:

Fy, C = Fy(A) + Fy(B)

Fy, C =0.67 N + 1.45 N = 2.12 N

Learn more about equilibrant force here: brainly.com/question/8045102

#SPJ1

3 0

2 years ago