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lbvjy [14]
3 years ago
11

A runner is running to the left with a speed of 8.0\,\dfrac{\text m}{\text s}8.0 s m ​ 8, point, 0, start fraction, start text,

m, end text, divided by, start text, s, end text, end fraction when she speeds up with constant acceleration for 2.0\,\text s2.0s2, point, 0, start text, s, end text to reach the finish line. The runner's final speed is 9.9\,\dfrac{\text m}{\text s}9.9 s m ​ 9, point, 9, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction to the left. What was the runner's acceleration as she sped up to the finish line?
Physics
2 answers:
Alla [95]3 years ago
4 0

Answer:

The runner's acceleration as she sped up to the finish line is 0.95m/s²

Explanation:

Acceleration is the change in velocity of a body with respect to time. It is expressed as;

Acceleration = change in velocity/time

Change in velocity = final velocity - initial velocity

Acceleration = final velocity - initial velocity / time

Given initial speed = 8.0m/s

Final speed = 9.9m/s

Time taken = 2.0s

Acceleration = 9.9-8.0 / 2.0

Acceleration = 1.9/2

Acceleration = 0.95m/s²

yawa3891 [41]3 years ago
4 0

Answer:

-0.95

Explanation:

saw it on khan academy

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Alex777 [14]

Answer:

yes

Explanation:

I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction

4 0
3 years ago
Read 2 more answers
 I will mark you as brainliest if you answer correctly
aleksklad [387]
(A) We can solve the problem by using Ohm's law, which states:
V=IR
where
V is the potential difference across the electrical device
I is the current through the device
R is its resistance
For the heater coil in the problem, we know V=220 V and R=220 \Omega, therefore we can rearrange Ohm's law to find the current through the device:
I= \frac{V}{R}= \frac{220 V}{220 \Omega}=1 A

(B) The resistance of a conductive wire depends on three factors. In fact, it is given by:
R= \rho \frac{L}{A}
where
\rho is the resistivity of the material of the wire
L is the length of the wire
A is the cross-sectional area of the wire
Basically, we see that the longer the wire, the larger its resistance; and the larger the section of the wire, the smaller its resistance.
6 0
3 years ago
Jennifer, who has a mass of 50.0 kg, is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to av
Assoli18 [71]

Answer:

Average force = 3.5 kN

Explanation:

Given:

Mass of Jennifer (m) = 50 kg

Initial velocity = 35 m/s

Time taken to stop body = 0.5 s

Find:

Average force

Computation:

v = u + at

0 = 35 + a(0.5)

Acceleration (a) =  - 70 m/s² = 70 m/s²

Average force = ma

Average force = (50(70)

Average force = 3500 N

Average force = 3.5 kN

6 0
3 years ago
The total charge a battery can supply is rated in mA⋅h , the product of the current (in mA ) and the time (in h ) that the batte
natita [175]

Answer: 0.2  hours

Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA  in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .

Besides, this battery has a voltage of 12 V

so by using the Ohm law we also know that V=R*I,

Fron this we can obtain:

I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA

then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA  in x time in the form:

1hour------- 1800 mA

x hour--------350 mA

time= 350/1800= 0.2 hour

4 0
3 years ago
An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s squared. What ar
Iteru [2.4K]
The direction of the electric field would be south. 

qE/m = 115 
<span>       E = 115*m/q </span>
<span>           = 115 * 9.1 * 10^(-31) / 1.67*10^(-19) </span>
<span>           = 762.87 * 10^(-12) </span>
<span>           = 6.27 x 10^-10 N/C
</span>
Hope this answers the question. Have a nice day. Feel free to ask more questions.
6 0
3 years ago
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