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maxonik [38]
3 years ago
6

Give an example of speed making a difference in the amount of kinetic energy. Tell how you know that kinetic energy amount is di

fferent in your example.
Please help this is due today
Physics
2 answers:
kykrilka [37]3 years ago
5 0

Answer:

1. A car moving 40 mph has four times as much kinetic energy as one moving 20 mph, while at 60 mph a car carries nine times as much kinetic energy as at 20 mph. Thus a modest increase in speed can cause a large increase in kinetic energy.

PLZ MARK BRAINLIEST THANK AND FIVE STAR:)

kari74 [83]3 years ago
5 0

Answer:

a car moving 40mph has four times as much kinetic energy as one moving 20 mph, while at 60 mph a car carries nine times as much kinetic energy as at 20 mph.

if you need any more info just dm me

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PLEASE ANSWER QUESTION FOR 10 POINTS
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C. It is a chemical change due to the change in temperature and gas production
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3 years ago
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Problem 3) Bob stands at the edge of the swimming pool holding a laser 1.5m above the ground. He shines the red laser beam onto
Vadim26 [7]

Answer:

d = 5.75m

Explanation:

Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

n1= refractive index of 1st medium= 1

n2=  refractive index of 2nd medium = 1.33

r= angle of reflection

therefore,

r = \sin^{-1}\frac{n_1\sin i}{n_2}

Here,

i = 90 - θ

\theta = \tan^-^1(\frac{1.5}{3} )\\\\=26.56^\circ

r = \sin^{-1}\frac{n_1\sin i}{n_2}

r = \sin^{-1}\frac{(1)\sin (90-26.56)}{1.33}\\\\r = 42.26m

\tan r = \frac{2.5}{d_1}

d_1 = \frac{2.5}{\tan (42.26)} \\\\d_1 = 2.75m

Therefore, the distance is

d = 3 + d₁

d = 3 + 2.75

d = 5.75m

6 0
3 years ago
Dave throws a 10 kg bowling ball straight up in the air. At the very tippy-top of its path, what is it's momentum?
svetoff [14.1K]

Answer:Zero

Explanation:

Given

mass of ball m=10\ kg

If the ball is thrown upward then at maximum point velocity of ball is zero because ball is no longer able to move upward

Momentum(P) of a particle is given by

P=mass\times velocity

P=10\times 0

P=0

Therefore at the highest point momentum is zero .

8 0
3 years ago
Please don’t troll. I need someone to actually answer these questions.
mash [69]

Answer:

-3+3 i think this is the answer

Explanation:

i think you can ask someone else sorry

4 0
3 years ago
Please help answer question​
nika2105 [10]

Answer:

C = 1.01

Explanation:

Given that,

Mass, m = 75 kg

The terminal velocity of the mass, v_t=60\ m/s

Area of cross section, A=0.33\ m^2

We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,

R = W

or

\dfrac{1}{2}\rho CAv_t^2=mg

Where

\rho is the density of air = 1.225 kg/m³

C is drag coefficient

So,

C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01

So, the drag coefficient is 1.01.

4 0
3 years ago
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