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zepelin [54]
3 years ago
13

Which observation supports a model of the nature of light in which light acts as a wave?

Physics
2 answers:
Lorico [155]3 years ago
5 0

Answer: A

Explanation:

yuradex [85]3 years ago
3 0

Answer:

The answer is A. Constructive interference

Explanation:

I took AP EX quiz.

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The graph of the relationship between the volume of a gas at constant temperature and its pressure is a(n)?
timurjin [86]
<span>When the difference between two results is larger than the estimates error, the result is</span>
5 0
3 years ago
The figure below shows a combination of capacitors. Find (a) the equivalent capacitance of combination, and (b) the energy store
velikii [3]

Answer:

A) C_{eq} = 15 10⁻⁶  F,  B)   U₃ = 3 J,  U₄ = 0.5 J

Explanation:

In a complicated circuit, the method of solving them is to work the circuit in pairs, finding the equivalent capacitance to reduce the circuit to simpler forms.

In this case let's start by finding the equivalent capacitance.

A) Let's solve the part where C1 and C3 are. These two capacitors are in serious

         \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_3}            (you has an mistake in the formula)

         \frac{1}{C_{eq1}} = (\frac{1}{30} + \frac{1}{15}) \  10^{6}

         \frac{1}{C_{eq1}} = 0.1   10⁶

         C_{eq1} = 10 10⁻⁶ F

capacitors C₂, C₄ and C₅ are in series

          \frac{1}{C_{eq2}} = \frac{1}{C_2} + \frac{1}{C_4} + \frac{1}{C_5}

          \frac{1}{C_{eq2} }  = (\frac{1}{15} + \frac{1}{30} +   \frac{1}{10} ) \ 10^6

          \frac{1}{C_{eq2} } = 0.2 10⁶

          C_{eq2} = 5 10⁻⁶ F

the two equivalent capacitors are in parallel therefore

          C_{eq} = C_{eq1} + C_{eq2}

          C_{eq} = (10 + 5) 10⁻⁶

          C_{eq} = 15 10⁻⁶  F

B) the energy stored in C₃

The charge on the parallel voltage is constant

is the sum of the charge on each branch

         Q = C_{eq} V

         Q = 15 10⁻⁶ 6

         Q = 90 10⁻⁶ C

the charge on each branch is

         Q₁ = Ceq1 V

         Q₁ = 10 10⁻⁶ 6

          Q₁ = 60 10⁻⁶ C

         Q₂ = C_{eq2} V

         Q₂ = 5 10⁻⁶ 6

         Q₂ = 30 10⁻⁶ C

now let's analyze the load on each branch

Branch C₁ and C₃

           

In series combination the charge is constant    Q = Q₁ = Q₃

          U₃ = \frac{Q^2}{2 C_3}

          U₃ =\frac{ 60 \ 10^{-6}}{2 \ 10 \ 10^{-6}}

          U₃ = 3 J

In Branch C₂, C₄, C₅

since the capacitors are in series the charge is constant Q = Q₂ = Q₄ = Q₅

          U₄ = \frac{30 \ 10^{-6}}{ 2 \ 30 \ 10^{-6}}

          U₄ = 0.5 J

7 0
3 years ago
an 18 ohm resistor and a 6 ohm resistor are connected in parallel to a battery, and the current in the 18 ohm resistor is found
riadik2000 [5.3K]

With 0.45 amp flowing through an 18-ohm resistor, the voltage across it is

       V  =  I R  =  (0.45) x (18)  =  <em>8.1 volts .</em>

"But I asked for the battery voltage!  That's the voltage across the resistor."

The ends of the resistor are connected directly to the battery terminals.
They're the same voltage.

"But what about the 6-ohm resistor ?  Where does that figure in ?"

In parallel, it doesn't.  It's also connected directly across the battery,
and it has its own current. 

In parallel, neither resistor knows or cares whether or not there are
any other resistors present.  In parallel, it makes no dif.


3 0
3 years ago
A parallel-plate capacitor with only air between its plates is charged by connecting the capacitor to a battery. The capacitor i
Delicious77 [7]

Answer:

3.91

Explanation:

Given that

Final reading of the voltmeter, V2 = 45 v

Initial reading of the voltmeter, V1 = 11.5 v

The dielectric constant k, of a material is usually given as

k = V2/V1

k = 45 / 11.5

k = 3.91

Therefore, the dielectric constant of the material as we've calculated above is sure to be 3.91.

I hope that helps you understand

5 0
4 years ago
Cuando es cuadrangular o home run en el beisbol
Svet_ta [14]

Answer:

when it's home run or home run in baseball

Explanation:

i looked it up on google translate

8 0
3 years ago
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