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Slav-nsk [51]
2 years ago
6

Are bath bombs pure substances or mixtures

Chemistry
2 answers:
mezya [45]2 years ago
3 0

Answer:

Yes.

Explanation:

Bath bombs are usually made from three key ingredients: baking soda, citric acid and cornstarch, said Frankie Wood-Black, an instructor in chemistry at Northern Oklahoma College and an experienced bath-bomb maker. Often, bath bombs also include dyes and perfumes, and sometimes they have epsom salt.

evablogger [386]2 years ago
3 0

Answer: yes

Explanation:

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3 years ago
Determine the amount of grams present in 3.25x1024 atoms of Lithium.
Sveta_85 [38]
When converted to a household measurement, 9 kilograms is approximately equal to a
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3 years ago
When the temperature of a sample of liquid increases , what else increases ?
Lubov Fominskaja [6]

Answer:

Its kinetic energy.

Explanation:

In a liquid, the molecules are so close together that there is very little empty space. A liquid also has a definite volume, because molecules in a liquid do not break away from the attractive forces. The molecules can, however, move past one another freely, and so a liquid can flow, can be poured, and assumes the shape of its container.

An increase in the temperature of a liquid causes an increase in the average speed of its molecules. As the temperature of a liquid increases, the molecules move faster thereby increasing the liquid's kinetic energy.

5 0
3 years ago
The chemical formula for magnesium oxide is 2MgO. The number 2 represents the number of ___.
patriot [66]

Answer:

Magnesium oxide molecules

Explanation:

3 0
3 years ago
10g of a non-volatile and non-dissociating solute is dissolved in 200g of benzene.
ehidna [41]

<u>Answer: </u>The molar mass of solute is 115 g/mol.

<u>Explanation:</u>

Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.

The expression for the calculation of elevation in boiling point is:

\text{Boiling point of solution}-\text{boiling point of pure solvent}=i\times K_b\times m

OR

\text{Boiling point of solution}-\text{Boiling point of pure solvent}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}} ......(1)

where,

Boiling point of pure solvent (benzene) = 80.10^oC

Boiling point of solution = 81.20^oC

i = Vant Hoff factor = 1 (for non-electrolytes)

K_b = Boiling point elevation constant = 2.53^oC/m

m_{solute} = Given mass of solute = 10 g

M_{solute} = Molar mass of solute = ? g/mol

w_{solvent} = Mass of solvent = 200 g

Putting values in equation 1, we get:

81.20-80.10=1\times 2.53\times \frac{10\times 1000}{M_{solute}\times 200}\\\\M_{solute}=\frac{1\times 2.53\times 10\times 1000}{1.1\times 200}\\\\M_{solute}=115g/mol

Hence, the molar mass of solute is 115 g/mol.

4 0
3 years ago
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