The mass of an object is 205 gram while the volume was measured to be 82.5 mL. What is this object's density?

g In animal tissues the rate of conversion of pyruvate to acetyl-CoA is regulated by the ratio of phosphorylated and dephosphory

Colt1911 [192]

Answer: seen below.

Explanation: since the different means use in treating rabbit muscle mitochondria containing PDH complex. I will give different reactions that occurs.

The mitochondria preparation responds as follow;

Active pyruvate dehydrogenase (dephosphorylated) is converted to inactive pyruvate dehydrogenase (phosphorylated) and the rate of conversion of pyruvate to acetyl-CoA decreases.

The phosphoryl group on pyruvate dehydrogenase (dephosphorylated) phosphate is removed enzymatically to give active pyruvate dephosphorylated which increases the rate of conversion of pyruvate to acetyl-CoA.

Malonate inhibit succinate dehydrogenase, and citrate accumulates. Accumulation of this citrate inhibits citrate synthase, and acetyl-CoA accumulates. Increased level of this acetyl-CoA inhibits pyruvate dephosphorylated and the rate of conversion of pyruvate to acetyl-CoA decreases.

5 0

3 years ago

a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3

aksik [14]

$\huge\boxed{♔︎Answer♔︎}$

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

half life time period = 3 hours

(a) The weight of sample after 3 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{3}{3} = 1$

The fraction of sample left

$\sf { \frac{1}{2} }^{1} = \frac{1}{2}$

Mass of the sample left

$\sf \frac{1}{2} \times 120 = \cancel\frac{120}{2} = 60g$

60g of sample is left after 3 hours

(b) The weight of sample after 6 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{6}{3} = 2$

The fraction of the sample left

$\sf { \frac{1}{2} }^{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

Mass of the sample left

$\sf \frac{1}{4} \times 120 = \cancel\frac{120}{4} = 30g$

30g of sample is left after 6 hours

(c) The weight of sample after 9 hours

$\textsf {No. of half lives} = \sf \cancel\frac{9}{3} = 3$

The fraction of sample left

$\sf { \frac{1}{2} }^{3} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$

Mass of sample left

$\sf \frac{1}{8} \times 120 = \cancel \frac{120}{8} = 15g$

15g of sample is left after 9 hours.

3 0

2 years ago

1. Concentrated HCl is 11.7M. What is the

SSSSS [86.1K]

Answer:

The concentration is 0,2925M

Explanation:

We use the formula

C initial x V initial = C final x V final

11,7 M x 25 ml = C final x 1000 ml

C final= (11,7 M x 25 ml)/1000 ml = 0, 2925 M

(This formula applies to liquid solutions)

6 0

4 years ago

Now describe the properties of the compound you picked(gold). Compare the properties of the compound with the properties of the

alexgriva [62]

Explanation:

Gold conducts heat and electricity. ...

Gold is ductile: It can be drawn out into the thinnest wire. ...

Gold is highly reflective of heat and light. ...

Gold is prized for its beauty. ...

Gold is malleable, so it can be flattened into extremely thin sheets.

on the other hand Gold consist of copper

Key Properties of Copper Alloys

Excellent heat conductivity.

Excellent electrical conductivity.

Good corrosion resistance.

Good biofouling resistance.

Good machinability.

Retention of mechanical and electrical properties at cryogenic temperatures.

Non-magnetic.

so the difference is that copper is less expensive and not priced with its beauty

8 0

3 years ago

Sound waves are created when something is caused to______

neonofarm [45]

Answer: to vibrate

Explanation:

6 0

3 years ago