Answer:
Explanation:
1) Se escoge la cadena con el mayor número de átomos de carbono. 2) Cuando hay dos cadenas posibles con el mismo número de átomos de carbono, se elige la que contenga el mayor número de triples ligaduras posibles. ... El átomo de carbono con la triple valencia libre se numera como 1.
Answer:
C5H7N
C10H14N2
Explanation:
ok so lets lay out this nicely
elements C H N
percentage 74 8.7 17.3
mass number 12 1 14
divided percentage by mass 6.167 8.7 1.2357
now divide the smallest number with the 4.99 7.04 1
rest for instance 1,237 is the smallest.
so 6.167÷1,237
and 8.7 ÷1.237
and 1,237 divide 1.237
now the ratio is C5H7N
now for molecular formula find Mr of C5H7N which is (12×5)+7+14=81
next divide 162.1÷81=2
so now for molecular formula just multipily everythng by 2
C10H14N2
Each energy sub-level corresponds to an orbital of a different shape which describes where the electron is likely to be found
The answer is:
a. 0.712 M
b. 0.210 M
c. 0.336 M
Molarity is a measure of the concentration of solute in a solution.
It can be expressed as moles of solute ÷ volume of solution:
c = n ÷V
where:
c - concentration of solute,
n - moles of solute
V - volume of solution
n can be expressed as:
<span>n = m ÷ Mr
</span>where:
<span>n - moles of solute
</span>m - mass of solute
Mr - relative molecular mass
a. We know volume:
V = 289.2 mL = 0.2892 L
We need n and c.
n = m ÷ Mr
m = 15.4 g
Mr (<span>KCl) = 74.55 g/mol
n = </span>15.4 g ÷ <span>74.55 g/mol
n = 0.206 mol</span>
Thus,
c = 0.206 mol ÷ <span>0.2892 L
c = 0.712 mol/L = 0.712 M
</span>b. We know volume:
V = 0.614 L
We need n and c.
n = m ÷ Mr
m = 14.4 g
Mr (CaCl₂<span>) = 110.98 g/mol
n = </span>14.4 g ÷ <span>110.98 g/mol
n = 0.129 mol</span>
Thus,
c = 0.129 mol ÷ <span>0.614 L
c = 0.210 mol/L = 0.210 M
</span>
c. We can use formula:
m₁V₁ = m₂V₂
<span>m₁ = 3 M
</span><span>V₁ = 28 mL= 0.028 L
</span><span>m₂ = ?
</span><span>V₂ = 0.250 L
</span>Thus:
3 M × 0.028 L = m₂× <span>0.250 L
</span> m₂ = 0.336 M
