Answer:
Mass of rock = 4533.4 kg
Explanation:
Percent composition is percentage by the mass of element present in the compound.
Given that the 
is 82 % by mass.
It means that 82 kg of is present in 100 kg of rock
To find the mass of rock which contains 2600 kg of iron
2600 kg = 2600*1000 g
2 moles of iron are present in 1 mole of
Molar mass of iron = 55.845 g/mol
Mass of 2 moles = 55.845 * 2 = 111.69 g/mol
Molar mass of = 159.69 g/mol
It means,
111.69 g of iron are present in 159.69 g of
1 g of iron is present in 159.69/111.69 g of
2600*1000 g is present in (159.69/111.69)*2600*1000 g of
Mass of = 3717378.47 g =3717.38 kg
Thus,
82 kg of is present in 100 kg of rock
1 kg of is present in 100/82 kg of rock
3717.38 kg of is present in (100/82)*3717.38 kg of rock
Mass of rock = 4533.4 kg
Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Answer:
Gold
Explanation:
Platinum has an atomic number of 78.
78 + 1 = 79
The element with atomic number 79 is Gold.
Hope this helps! Let me know if you have any questions :)
Answer:
12.7551
Explanation:
The given chemical equation follows:
The equilibrium constant for the above equation is 0.28.
We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:
The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
<u>Hence, the value of equilibrium constant for reverse reaction is 12.7551.</u>
Answer:
°C = K - 273.15
Explanation:
Take your Kelvin temperature and subtract 273.15. Your answer will be in Celsius
