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Vilka [71]
4 years ago
13

Which metal will spontaneously react with Zn2+

Chemistry
1 answer:
Daniel [21]4 years ago
4 0

The options of the question is not given so the options are;

(1) Mn(s)

(2) Cu(s)

(3) Ni(s)

(4) Ba(s)

Answer: Mn(s)

Explanation:

The spontaneous reaction depends on the Eo value. The positive Eo value are spontaneous and the negative Eo values are not spontaneous.

so, here the Eo values are:

Eo Zn2+/Zn = -0.763v

Eo Mg2+/Mg = 2.37v

Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn

=  -0.763 - (-1.18)

 = 0.417v

Whereas, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn

=  -2.37 - (-1.18) = -1.19v

Thus, Mn(s) metal will spontaneously react because it has a positive  Eo value and  Zn2+(aq), but will not spontaneously react with Mg2+(aq) because it has negative Eo value.

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alisha [4.7K]

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8 0
4 years ago
Explain how there can be more heat energy in an iceburg than in a pot of boiling water
vlada-n [284]

Heat energy is the amount of heat there is in a substance. This may be cold heat or warm heat. Temperature is how hot or cold a substance is. So because there is a higher volume of heat in the iceberg, we say it has more heat energy.
3 0
3 years ago
NEED HELP ASAP PLEASE
Lostsunrise [7]

Answer:

here hope it helps

Explanation:

covalent bonds

5 0
3 years ago
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You want to minimize an objects thermal energy loss on a cold day. How does heat energy transfer affect thermal energy loss?
san4es73 [151]

Answer:

4- A material that transfers heat energy more easily than another material will experience a greater rate of thermal energy loss than an object that does not transfer heat energy easily.

Explanation:

Thermal energy loss has to do with loss of heat energy by a body to another body or its environment. The aim of the process is usually the attainment of thermal equilibrium between the body and its environment.

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6 0
3 years ago
Isotope Atomic Mass (amu) Percent Abundance
exis [7]

Answer:

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

Explanation:

Given data:

Atomic mass of silicon= ?

Percent abundance of Si-28 = 92.21%

Atomic mass of Si-28 = 27.98 amu

Percent abundance of Si-29 = 4.70%

Atomic mass of  Si-29 = 28.98 amu

Percent abundance of Si-30 = 3.09%

Atomic mass of  Si-30 = 29.97 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100

Average atomic mass =  2580.04 +136.21+92.61 / 100

Average atomic mass = 2808.86 / 100

Average atomic mass  = 28.08amu.

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

7 0
3 years ago
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