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Nataly [62]
3 years ago
13

Consider the mechanism. Step 1: A+B↽−−⇀CA+B↽−−⇀C equilibrium Step 2: C+A⟶DC+A⟶D slow Overall: 2A+B⟶D2A+B⟶D Determine the rate la

w for the overall reaction, where the overall rate constant is represented as ????.
Chemistry
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

rate = k[A][B] where k = k₂K

Explanation:

Your mechanism is a slow step with a prior equilibrium:

\begin{array}{rrcl}\text{Step 1}:& \text{A + B} & \xrightarrow [k_{-1}]{k_{1}} & \text{C}\\\text{Step 2}: & \text{C + A} & \xrightarrow [ ]{k_{2}} & \text{D}\\\text{Overall}: & \text{2A + B} & \longrightarrow \, & \text{D}\\\end{array}

(The arrow in Step 1 should be equilibrium arrows).

1. Write the rate equations:

-\dfrac{\text{d[A]}}{\text{d}t} = -\dfrac{\text{d[B]}}{\text{d}t} = -k_{1}[\text{A}][\text{B}] + k_{1}[\text{C}]\\\\\dfrac{\text{d[C]}}{\text{d}t} = k_{1}[\text{A}][\text{B}] - k_{2}[\text{C}]\\\\\dfrac{\text{d[D]}}{\text{d}t} = k_{2}[\text{C}]

2. Derive the rate law

Assume k₋₁ ≫ k₂.  

Then, in effect, we have an equilibrium that is only slightly disturbed by C slowly reacting to form D.  

In an equilibrium, the forward and reverse rates are equal:

k₁[A][B] = k₋₁[C]

[C] = (k₁/k₋₁)[A][B] = K[A][B] (K is the equilibrium constant)

rate = d[D]/dt = k₂[C] = k₂K[A][B] = k[A][B]

The rate law is  

rate = k[A][B] where k = k₂K

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How many grams are in 5.00 moles of sodium carbonate?
dimulka [17.4K]

Answer:

= 529.9422

grams

Explanation:

5  moles Sodium Carbonate

= 529.9422

grams

8 0
3 years ago
A volume of 80.0 mL of aqueous potassium hydroxide (KOH) is titrated against a standard solution of sulfuric acid (H2SO4). What
yaroslaw [1]

Answer:

0.478 M

Explanation:

Let's consider the neutralization reaction between KOH and H₂SO₄.

2 KOH + H₂SO₄ → K₂SO₄ + 2 H₂O

12.7 mL of 1.50 M H₂SO₄ react. The reacting moles of H₂SO₄ are:

0.0127 L × 1.50 mol/L = 0.0191 mol

The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of KOH are 2 × 0.0191 mol = 0.0382 mol

0.0382 moles of KOH are in 80.0 mL. The molarity of KOH is:

M = 0.0382 mol/0.0800 L = 0.478 M

3 0
3 years ago
If the mass of 293nv is 293.10 amu and that of 295nv is 295.45 amu , what is the atomic weight of nv?
ycow [4]

Answer;

294.13 amu

Solution;

-293nv is 293.10 amu and that of 295nv is 295.45 amu

293.05+295.2=588.25

588.25/2= 294.13 amu

an amu of 294.13 using significant figures

3 0
3 years ago
If one jellybean weighs 0.350g how many jelly beans are in 504g of jellybeans?
allsm [11]

Answer:

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Explanation:

Divide 504g by 0.350g

4 0
3 years ago
Mole ratios how can the coefficients in a chemical equation be interpreted
navik [9.2K]

Answer:

The coefficient in a balanced chemical equation  indicates the mole ratio of both reactants and products.  

Explanation:

For example lets consider the reation between Hydrogen and Oxygen to form water:

2H2 + O2 ----------------------- 2H2O

In this reaction, the coefficients of the balanced reaction can be transformed to Mole ratio according to Avogadro's Law which states that at standard temperature and pressure, equal volume of gases contain the same  number of moles.

So the mole ratio for the above equation is  the  ratio of the coefficient:

2moles     :     1 mole               :          2 moles

8 0
3 years ago
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