Answer:
8.87 m/s^2
Is the same for both planets
Explanation:
Hello!
The surface gravity can be calculated from Newton's Law of Gravitation and Newton's Second Law :
ma = F =G Mm/r^2
Solving for a:
a = G M/r^2
And the surface graity g = a(R), that is, the surface gravity is equal to the acceleration evaluated at the radius of the planet:
g = G M/R^2
Since G is a constant, we need to evaluate M/R^2 for both to know in which planet the surface gravity is the geratest:
M_u/R_u^2 = 1.323 x 10^11 kg/m^2
M_v/R_v^2 = 1.323 x 10^11 kg/m^2
It turns out that the surface gravity in both planets is the same! which is:
g = G M_u/R_u^2
= ( 6.67408 × 10-11 m^3 / (kg s^2) ) *( 1.323 x 10^11 kg/m^2)
= 8.87 m/s^2
*as you can check on google*
You would feel the same weigth in both planets, however you wil feel lighter in these planets than in earth.
<span>The answer is "preconscious". (:</span>
The relationship between the mass of the celestial bodies relative strengths is that the bigger the planet the more gravity pulls you down for example compare Earth with a human, if a person jumps gravity pulls you down compare it to REAL LIFE you see how fast and hard you land but on Pluto or Mercury, there is no gravity just like on the moon that's why when see people on the moon jump, they seem to float. So the more mass or how much a planet can hold gravity brings you down faster and stronger than regular.
The observation point on Earth and the two stars form a triangle. The two sides of the triangle are 23.3 ly and 34.76 ly and their included angle is 76.04°. We can use the cos rule to find the third side, which is the distance between the two stars.
c² = a² + b² - 2abCos(C)
c² = (23.3)² + (34.76)² - 2(23.3)(34.76)Cos(76.04)
c = 36.88 light years.