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Advocard [28]
3 years ago
15

At a party, you see someone on the floor with grayish skin, having

Chemistry
2 answers:
denis-greek [22]3 years ago
6 0
All of above. Overdoses have side effects like troubles breathing and other
Tpy6a [65]3 years ago
3 0
All of the above an overdose of anything can make you have symptoms
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Study this diagram of a flowering tree’s life cycle. What is the error in the diagram? A. stage 1 B. stage 2 C. stage 3 D. stage
Ksivusya [100]

c. . stage 3 hoped i helped with the question

6 0
3 years ago
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Using the measurements in the table, determine which unidentified metal has the lowest density
Oliga [24]
C is the correct answer because density is mass per unit volume and when you divide it we that volume is greater than mass so density is less density density is directly proportional to Mass Density is inversely proportional to volume
3 0
3 years ago
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How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

•Molar mass of Silver Ag= 107.9g/mol

•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

•Molecular weight of Ag2S= 215.8g/mol + 32g/mol= 247.8g/mol

•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

xg= 215.8g × 125g / 247.8g

xg= 26975g/247.8

xg= 108.85g

Therefore, 108.9g of Silver can be produced from 125g of Ag2S

3 0
3 years ago
Read 2 more answers
Elements that do not have full outer electron shells will donate, share, or take from other atoms. Choose the items that have th
Gnesinka [82]

Answer:

Ok...

Answer: YTH/JYG

Explanation:

AI+ZN+H=YTH

7 0
3 years ago
What is the concentration of a sodium hydroxide solution if 14.5 mL of it are exactly neutralized by 30.0 mL of a 0.500 M hydroc
rusak2 [61]

Answer:

1.03 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

30.0 mL (0.0300 L) of 0.500 M HCl react.

0.0300 L × 0.500 mol/L = 0.0150 mol

Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.

Step 4: Calculate the molar concentration of NaOH

0.0150 moles of NaOH are in 14.5 mL (0.0145 L).

M = 0.0150 mol/0.0145 L = 1.03 M

4 0
3 years ago
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