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VladimirAG [237]
2 years ago
6

In a laboratory, bunsen burner is used to increase the temperature of lime from 10 °C to 50 °C with the thermal energy of 80000

J. If the mass of the lime is 20 kg the specific heat capacity of the lime would be a 50 J/g C b 100 J/g C c 75 J/g C d 25 J/g C
Chemistry
1 answer:
galina1969 [7]2 years ago
3 0

Answer:

c = 100 J/g.°C

Explanation:

Given data:

Mass of lime = 20 g

Heat absorbed = 80,000 J

Initial temperature = 10°C

Final temperature = 50°C

Specific heat capacity of lime = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 50°C - 10°C

ΔT = 40°C

80,000 J = 20 g×c×40°C

80,000 J = 800°C×c

c = 80,000 J /800g.°C

c = 100 J/g.°C

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<span>Fe(OH)₃ and CuO
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<span>Answer:
</span>

<span>Cu(OH)₂ and H₂S
</span>

Justification:


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<span>Cu(OH)₂ + H₂S → CuS + 2H₂O
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6 0
3 years ago
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sladkih [1.3K]

Answer:

The answers to your question are given below

Explanation:

The equation for the reaction is given below:

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Reactants >>>>>> Number of atoms

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Products >>>>>>> Number of atoms

Potassium (K) >>> 2 × 1 = 2

Chlorine (Cl) >>>> 2 × 1 = 2

Oxygen (O) >>>>> 3 × 2 = 6

8 0
2 years ago
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