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maks197457 [2]
3 years ago
6

You are given a long length of string and an oscillator that can shake one end of the string at any desired freqeuency

Physics
1 answer:
Anastasy [175]3 years ago
7 0
Based on this given information, the oscillator can perform a simulated oscillation on the given string. However, this is dependent on the speed and length of the oscillator and string.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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Decide which of the following sports can be the most beneficial in achieving cardiovascular
Anvisha [2.4K]

If you mean beneficial in improving cardiovascular endurance then the best sports would be swimming, running, basketball, rowing and squash.

3 0
3 years ago
A cheetah can maintain its maximum speed of 100 km/hr for 30.0 seconds. What minimum distance must a gazelle running 80.0 km/hr
german

Explanation:

Suppose the cheetah is initially positioned at x=0 (m) from the reference, and the gazelle is intially at poisiton x=d (m).

Then, at the worst case, that is when cheetah is running at the maximum case, the position of the gazelle relative to the reference must be larger than that of cheetah.

In equation form,

0\text{ km}+\frac{100\text{ km}}{1 \text{ hr}}\cdot30\text{ s }\cdot\frac{1\text{ hr}}{3600\text{ s}}\le d \text{ km}+\frac{80\text{ km}}{1 \text{ hr}}\cdot30\text{ s }\cdot\frac{1\text{ hr}}{3600\text{ s}}

(100-80)\cdot \frac{30}{3600}\le d

d\ge \frac16\text{ km}=166.66 \text{m}

8 0
3 years ago
At a given point on a horizontal streamline in flowing air, the static pressure is â2.0 psi (i.e., a vacuum) and the velocity is
Nastasia [14]
At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²

Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s

Point 2 (stagnation):
At the stagnation point, the velocity is zero.

The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
     = 314.37 lb/ft²
     = 314.37/144 = 2.18 lb/in²

Answer: 2.2 psi

5 0
3 years ago
The ability of a singer to shatter glass is due to: <br> bending of a wave around an obstacle
Rzqust [24]
The ability of singers to shatter glass is due to the control of frequency in their voices. The sound waves will vibrate the air particles that surround the glass at its resonant frequency. The glass will break if a singer sings too loudly.
8 0
3 years ago
Read 2 more answers
A 3-kg mass is in free fall. What is the velocity of the mass after 7 seconds??
dmitriy555 [2]
69 ms. I hope that helps
6 0
3 years ago
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