The correct option is (b) 5n
As a result, there is a net downward force of 5N operating on the object.
The resultant force is the force that results from adding the vector sums of all the forces operating on an item. The combined action of all the acting forces on the object produces the same effect as the resulting force. When determining the resulting force, the direction of the forces must be taken into account.
Given;
The northward force is Fn = 10N
The southward force is Fs = 15N
Required;
The net force on the mobile phone is Fnet = ?N
The object's weight exerts downward pressure, and upward resistance exerts upward pressure. The vector sum of these two forces will be the net force.
Fnet = Fs - Fn (Considering the direction downward as positive)
Fnet= 15N - 10N
Fnet = 5N
As a result, there is a net downward force of 5 N operating on the object.
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Answer:
Small sparks can lead to huge explosion if they are left unattended.
Explanation:
Small sparks are not harmful but if these sparks happen near some hazardous material or object then it could lead to heavy explosion. If there is some chemical substance near the spark or there are magnetic lines which can explode the spark then these minor sparks could result in heavy disastrous explosion.
Answer:
Approximately
.
Explanation:
Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.
Look up the Rydberg constant for hydrogen:
.
Look up the speed of light in vacuum:
.
Look up Planck's constant:
.
Apply the Rydberg formula to find the wavelength
(in vacuum) of the photon in question:
.
The frequency of that photon would be:
.
Combine this expression with the Rydberg formula to find the frequency of this photon:
.
Apply the Einstein-Planck equation to find the energy of this photon:
.
(Rounded to three significant figures.)
Answer:
The elevator must be moving upward.
Explanation:
During the motion of an elevator, the weight of the person deviates from his or her actual weight. This temporary weight during the motion is referred to as "Apparent Weight". So, when the elevator is moving downward, the apparent weight of the person becomes less than his or her actual weight.
On the other hand, for the upward motion of the elevator, the apparent weight of the person becomes more than the actual weight of that person.
Since the apparent weight (645 N) of the student, in this case, is greater than the actual weight (615 N) of the student.
<u>Therefore, the elevator must be moving upward.</u>