Answer:
It would be PE=16kg * 9.8 m/s^2 * 1m = 160 J
Explanation:
The person who asked this question ended up answering his own question so I'm here to let you know all that the answer was founded by the person whos posted the question himself full credit goes to him :)
Total internal reflection. Although I'm not 100%
Mechanical or Electromagnetic
Answer:
a) A = [m /s²]
, B = [m /
]
, b) v = a to + 2B/3 
Explanation:
a) to define the units of the constants, we see that the left part has units of acceleration so the right part must also have the same units
A = [m /s²]
B = [m / s²]
B = [m /
]
b) We must use the definition of acceleration
a = dv / dt
dv = adt
We integrate
∫ dv = ∫ (A + B
) dt
v = a t + B 2/3
We evaluate between:
the lower limit t = 0 v = o and the upper limit t = to v = v
v = a to + 2B/3 
c) Let's use the definition of speed
v = dx / dt
dx = v dt
∫ dx = ∫ (a t + 2B/3
) dt
x = a t²/2 + 2b/3 2/5 
For the interval t = 0 and t = to, we evaluate the integral
x = A/2 t₀² + 4B/15 √t₀⁵
Answer:
56 m/s
Explanation:
The time we are considering is
t = 15 s
The vertical velocity of the projectile is given by

where
is the initial vertical velocity
is the acceleration due to gravity
Substituting t=15 s, we find the vertical velocity of the projectile at that time:

where the negative sign means the direction is now downward.
The horizontal velocity does not change since there are no forces acting along that direction, so it remains constant:

So, the magnitude of the velocity at the moment of impact is
