Answer:
C3H6O
Explanation:
Data obtained from the question. This includes:
Carbon (C) = 0.62069 g
Hydrogen (H) = 0.103448 g
Oxygen (O) = 0.275862 g
The empirical formula can be obtained as follow:
Step 1:
Divide by their molar mass.
C = 0.62069 / 12 = 0.0517
H = 0.103448 / 1 = 0.103448
O = 0.275862 / 16 = 0.0172
Step 2:
Divide by the smallest number.
C = 0.0517 / 0.0172 = 3
H = 0.103448 / 0.0172 = 6
O = 0.0172 / 0.0172 = 1
Step 3:
Writing the empirical formula.
The empirical formula is C3H6O
Enthalpy refers to the total energy of a system. Hope this helped!
I believe the correct answer is C. The amount of catalyst is the same at the end as at the beginning of the reaction. Catalysts can't be consumed by the reaction thus is not D.
Answer:
B
Explanation:
wet air is known as water vapor
please mark brainliest
Answer:
Measure 20mL of the stock
Explanation:
All we need to do is to find the volume of the stock solution needed. This is illustrated below:
C1 = 2M
V1 =?
C2 = 0.400 M
V2 = 100mL
C1V1 = C2V2
2 x V1 = 0.4 x 100
Divide both side by 2
V1 = ( 0.4 x 100) /2
V1 = 20mL
Therefore, to prepare the solution, we will measure 20mL of the stock solution and make it up to the 100mL mark.
