Answer:
367.1 cm³
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 300 cm³
Initial temperature (T₁) = 40 °C
Final temperature (T₂) = 110 °C
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273.15
Initial temperature (T₁) = 40 °C
Initial temperature (T₁) = 40 °C + 273.15
Initial temperature (T₁) = 313.15 K
Final temperature (T₂) = 110 °C
Final temperature (T₂) = 110 °C + 273.15
Final temperature (T₂) = 383.15 K
Finally, we shall determine the final volume (i.e the new volume) of the balloon. This can be obtained by using the Charles' law equation as illustrated below:
Initial volume (V₁) = 300 cm³
Initial temperature (T₁) = 313.15 K
Final temperature (T₂) = 383.15 K
Final volume (V₂) =?
V₁/T₁ = V₂/T₂
300 / 313.15 = V₂ / 383.15
Cross multiply
313.15 × V₂ = 300 × 383.15
313.15 × V₂ = 114945
Divide both side by 313.15
V₂ = 114945 / 313.15
V₂ = 367.1 cm³
Therefore, the new volume of the balloon is 367.1 cm³
