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galina1969 [7]
1 year ago
8

The formula for a lutetium carbonate compound is Lu2(CO3)3. What would be the formula for a lutetium nitrate compound given that

the charge of lutetium is the same in both compounds
Chemistry
1 answer:
emmasim [6.3K]1 year ago
4 0

Lu(NO₃)₃ would be the formula for a lutetium nitrate compound, given that the charge of lutetium is the same in both compounds.

From Lu2(CO₃)₃, we can determine the charge of the variable charge transition metal Lu has a charge of 3, as CO₃ has a 2⁻ charge (3⁻² = 6⁻¹, 6/2 = 3). Then, we apply this to nitrate, which has a charge of 1⁻. Balance charges, reduce, and you get Lu(NO₃)₃.

<h3><u>Nitrates:</u></h3>

With the chemical formula NO⁻₃, nitrate is a polyatomic ion. This ion is found in salts, which are known as nitrates. Fertilizers and explosives frequently contain nitrates as a component. Nearly all inorganic nitrates are water soluble. Bismuth oxynitrate is an illustration of an insoluble nitrate.

Natural compounds called nitrates (or nitrites) can be found in the soil, air, and water. In order to prevent the growth of germs and to improve the flavor and color of food, nitrates are also employed as a food additive.

To view similar questions based on nitrates of different compounds, refer to:

brainly.com/question/5346392

#SPJ4

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Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

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moles of Copper = ?

mass of Aluminum = 29 g

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Balanced Chemical reaction

                  3 CuSO₄   +  2 Al   ⇒   3 Cu   +  Al₂(SO₄)₃

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                160 g of CuSO₄  ----------------- 1 mol

                156 g                   -----------------  x

                      x = (156 x 1) / 160

                      x = 0.975 moles

               27 g of Al -------------------------- 1 mol

               29 g of Al -------------------------- x

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Calculate proportions to find the limiting reactant

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Experimental  0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.      

                    3 moles of CuSO₄ ------------------ 3 moles of Cu

                 0.975 moles of CuSO₄ ---------------  x

                         x = (0.975 x 3)/3

                        x = 0.975 moles of Cu were obtained.        

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