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3 years ago

5

Give the chemical symbol of an element in the third period (row) of the periodic table with two 3s electrons and no 3p electrons

.

1 answer:

lidiya [134]3 years ago

3 0

Answer:

Mg

Explanation:

The element in the third row with two 3s electrons and no 3p electrons is magnesium — Mg.

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3 years ago

0.000000655 mL in scientific notation

alina1380 [7]

Answer:

<u>The answer is 6.55 * 10⁻⁷</u>

Explanation:

Let's write 0.000000655 mL in scientific notation:

The first step is you have to move the decimal place until you have a number between 1 and 10. If you keep moving the decimal point to the right in 0.000000655 you will get 6.55.

Now, the second step is you count how many places you moved the decimal point. You moved it 7 places to the right to change 0.000000655 to 6.55.

Finally, You need to show that you moved the decimal point 7 places to the right by noting that the number should be multiplied by 10⁻⁷ because a power of ten with a negative exponent, such as 10⁻⁷, means the decimal was moved to the right.

<u>The answer is 6.55 * 10⁻⁷</u>

3 0

3 years ago

The ph of a fruit juice is 3.2. find the hydronium ion concentration, left bracket upper h 3 upper o superscript plus right bra

melomori [17]

pH is referred to as the scale to describe the hydronium ion concentration of a

solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.

pH can be calculated using the formula:

$pH = - log [H_{3}O^{+}]$

Given the pH of solution is 3.2.

Finding out the concentration of hydronium ion from pH.

$pH = - log[H_{3}O^{+}]$

$3.2 = - log [H_{3}O^{+}]$

$[H_{3}O^{+}] = 10^{-3.2}$

$[H_{3}O^{+}] = 6.3 * 10^{-4} M$

Therefore, the hydronium ion concetration of the solution is $6.3 * 10^{-4} M$

3 0

3 years ago

A concrete pile from a waterfront pier was pulled from the harbor water at port hueneme california. It's dimensions we're 14in x

Anna [14]

The surface area expressed in square feet of a single face of a pile is 1.45 square feet.

<u>Explanation:</u>

The dimensions of the pillar are given as 14 in $\times$ 14 in

(1 feet = 12 inch)

According to the pillar dimensions mentioned in the problem, the length of the pillar should be 15 inches, height by 14 inches and the width by 14 inches.

There will be two surface areas of the concrete pile, one implies side surface area and the other is end surface area.

For calculating the side surface area,

Area of the side surface = 14 in $\times$ 15 in

= $14 in.$ $\times$ $\frac{1 ft.}{12 in.}$

= 1.16 $\times$ 1.25

= 1.45 square feet.

(In the given question, only a single face is asked so there is no need to find the surface area of the end face.)

8 0

3 years ago

Multiply the following and express your answer in appropriate scientific notation, and a correct number of significant figures.

7nadin3 [17]

Answer:

2

Explanation:

8 0

2 years ago