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3 years ago

Hello BEANS would you like to play a game knok knok

Chemistry

2 answers:

blsea [12.9K]3 years ago

6 0

Answer:

Maybe later, not right now. Tell you when.

kodGreya [7K]3 years ago

3 0

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Identify which location in the periodic table you would have the largest atomic radii.

bearhunter [10]

Answer:

left to right across a period when it decreases and when it increases top to bottom in a group,

hope i helped

5 0

3 years ago

How many moles of lithium are in 18.2 grams of lithium

Doss [256]

Answer:

I think 2.6 sorry if its wrong

6 0

3 years ago

Read 2 more answers

from the following equation in which decomposition of CaCO3 takes place, give your justification. CaCO3 gives Ca +CO2

IceJOKER [234]

Answer:

CaCO₃(s) => CaO(s) + CO₂(g) ... GpIIA Decomp

Explanation:

Metallic Carbonates decompose into a metallic oxide and carbon dioxide.

Examples:

Na₂CO₃(s) => Na₂O(s) + CO₂(g) ... GpIA Decomp

MgCO₃(s) => MgO(s) + CO₂(g) ... GpIIA Decomp

7 0

3 years ago

What are some things we breathe in

Gre4nikov [31]

Answer:

The majority of the air we breathe is made up of nitrogen and oxygen, though you'll also find argon, carbon dioxide and other gases in trace amounts.

Explanation:

7 0

3 years ago

What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according

ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

Step 1: The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

Step 2: Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

Step 3: Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

Step 4: Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0

3 years ago