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Black balls with blue waffles
Answer:
Part a)
Width of the slit is

Part b)
Ratio of intensity is given as

Explanation:
Part a)
As we know by the formula of diffraction we will have

so we have


so we will have


Part b)
As we know that the intensity in diffraction pattern is given as


so for angle 45 degree



Answer:
The same current flows through each resistor in series. Individual resistors in series do not get the total source voltage, but divide it. The total resistance in a series circuit is equal to the sum of the individual resistances: RN(series)=R1+R2+R3+…
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